The values of a and b are 1/4 and 1/5 respectively
<h3>How to determine the true statement?</h3>
The function is given as:
16x^2 - 25y^2 = 1
The above function is a horizontal hyperbola.
A horizontal hyperbola that passes through the origin is represented as:
![\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1](https://tex.z-dn.net/?f=%5Cfrac%7Bx%5E2%7D%7Ba%5E2%7D%20-%20%5Cfrac%7By%5E2%7D%7Bb%5E2%7D%20%3D%201)
Rewrite 16x^2 - 25y^2 = 1 as
![\frac{x^2}{1/16} - \frac{y^2}{1/25} = 1](https://tex.z-dn.net/?f=%5Cfrac%7Bx%5E2%7D%7B1%2F16%7D%20-%20%5Cfrac%7By%5E2%7D%7B1%2F25%7D%20%3D%201)
By comparison, we have:
![a^2 = \frac{1}{16}](https://tex.z-dn.net/?f=a%5E2%20%3D%20%5Cfrac%7B1%7D%7B16%7D)
![b^2 = \frac{1}{25}](https://tex.z-dn.net/?f=b%5E2%20%3D%20%5Cfrac%7B1%7D%7B25%7D)
Solve for a and b
![a = \frac{1}{4}](https://tex.z-dn.net/?f=a%20%3D%20%5Cfrac%7B1%7D%7B4%7D)
![b = \frac{1}{5}](https://tex.z-dn.net/?f=b%20%3D%20%5Cfrac%7B1%7D%7B5%7D)
Hence, the values of a and b are 1/4 and 1/5 respectively
Read more about hyperbola at:
brainly.com/question/27799190
#SPJ1
Man I think it's c, and it's definitely not d, but c b/c the two lines on BC and EF means that they are congruent
If you would like to evaluate A^2 for A = - 3, you can do this using the following step:
A^2 = (-3)^2= +9 = 9
If you would like to evaluate 2 * A for A = -3, you can do this like this:
2 * A = 2 * (-3) = -6