Send it to me and I'd be happy to help! :)
First, make sure you convert both equations into standard form. Your two equations would be 2x+2y=38 and -x+y=3. Then multiply the bottom by 2. So your new equations would be 2x+2y=38 and -2x+2y=6. The x would cancel out and you would continue solving for y. y would equal 11 and then you would plug it back into an original equation. When you plug and solve for x, you would get x=8. So your answer would be (8,11)
Answer:(x^5−4) and (x^10+4x^5+16)
Your question is a bit unclear, but if you mean which lines are parallel to this one then I have an answer.
1/2*4=2 so this line would be y=2 which means it is a horizontal line. Therefore, any other horizontal line would be parallel to it. So just pick a value for Y to equal and that will be your answer.
ie. y=7
Solve, for the first variable in one of the equation, the substitute the final result into the other equation
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