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Luba_88 [7]
3 years ago
14

(5x2 – 3) + (8x2 - 1)

Mathematics
2 answers:
sineoko [7]3 years ago
5 0

Answer:

Step-by-step explanation:

(5x2-3)+(8x2-1)

 13x squared - 4

 (5 • (x2)) -  3) +  (23x2 -  1)

 (5x squared -  3) +  (8x squared - 1)

 13x squared - 4

GalinKa [24]3 years ago
3 0

Answer:

13x^2-4

Step-by-step explanation:

(5x^2-3)+(8x^2-1)=

5x^2+8x^2-3-1=

13x^2-4

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Answer:

no solution

Step-by-step explanation:

ya gotta use your eyes and brain huney. it aint that hard. kk? but ill still explain for you.

since x+y=6 and x+y=4. then 4=6. but that is false so no solution.

YOUR WELCOME!

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A manufacturer reported a sample mean = 22.0 g and a sample standard deviation = 2.5 g based on a sample of 20 of their products
tester [92]

Answer:

n=(\frac{1.640(2.5)}{2})^2 =4.2 \approx 5

So the answer for this case would be n=5 rounded up to the nearest integer

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=22 represent the sample mean

\mu population mean (variable of interest)

s=2.5 represent the sample standard deviation

n represent the sample size  

ME = 2 represent the margin of error accepted

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

The margin of error is given by this formula:

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}    (2)

And on this case we have that ME =2 and we are interested in order to find the value of n, if we solve n from equation (2) we got:

n=(\frac{z_{\alpha/2} s}{ME})^2   (3)

We can use as estimator for the population deviation the sample deviation \hat \sigma = s

The critical value for 90% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.05;0;1)", and we got z_{\alpha/2}=1.640, replacing into formula (3) we got:

n=(\frac{1.640(2.5)}{2})^2 =4.2 \approx 5

So the answer for this case would be n=5 rounded up to the nearest integer

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X+3Y=6 turned into slope-intercept form
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Y=-1/3x+2

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