Question

Wen is factoring the polynomial, which has four terms. 6x3 – 12x2 7x – 14 6x2 (x – 2) 7(x – 2) Which is the completely factored form of his polynomial? (6x2 7) (x –2) (6x2 – 2) (x 7) (6x2 2) (x – 7) (6x2 – 7) (x 2).

Answer 1

The factorized form of the polynomial 6x³ – 12x² + 7x – 14 is (6x²+7)(x–2).

What is a factor?

A factor of n is a number which when multiplied by another number gives us the number n.

In order to factorize the polynomial 6x³ – 12x² + 7x – 14, we need to take the common terms out of the given polynomial, therefore, the polynomial can be factorized as,

$6x^3-12x^2+7x - 14$

Taking the common term 6x² out from the first two terms, and then 7 from the next two terms, therefore, the polynomial can be written as

$6x^3-12x^2+7x - 14 \\\\= 6x^2(x-2)+7(x-2)\\\\=(6x^2 +7)(x-2)$

Hence, the factorized form of the polynomial 6x³ – 12x² + 7x – 14 is (6x²+7)(x–2).

Learn more about Factors:

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Answer 2

Answer:

A

Step-by-step explanation: