Answer:
(0,4.5)
Step-by-step explanation:
Y=mx+b
m=slope
given
y=4x+5
m=4=slope
2.
for the points (x1,y1) and (x2,y2), the slope of the line passing trhough those points is (y2-y1)/(x2-x1)
given
(1,6) and (3,10)
slope=(10-6)/(3-1)=4/2=2
function 1 slope is 4
function 2 slope is 2
4>2
the first one has greater rate of change
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Answer: Option 'c' is correct.
Step-by-step explanation:
Since we have given that
the optimized solution of a linear program to an integer as it does not affect the value of the objective function.
As if we round the optimized solution to the nearest integer, it does not change the objective function .
while it is not true that it always produces the most optimal integer solution or feasible solution.
Hence, Option 'c' is correct.
1) The average increase in the level of CO2 emissions per year from years 2 to 4 is:
Average=[f(4)-f(2)]/(4-2)=(29,172.15-26,460)/2=2,712.15/2=1,356.075 metric tons. The first is false.
2) The average increase in the level of CO2 emissions per year from years 6 to 8 is:
Average=[f(8)-f(6)]/(8-6)=(35,458.93-32,162.29)/2=3,296.64/2=1,648.32 metric tons. The second is false.
3) The average increase in the level of CO2 emissions per year from years 4 to 6 is:
Average=[f(6)-f(4)]/(6-4)=(32,162.29-29,172.15)/2=2,990.14/2=1,495.07 metric tons. The third is false.
4) The average increase in the level of CO2 emissions per year from years 8 to 10 is:
Average=[f(10)-f(8)]/(10-8)=(39,093.47-35,458.93)/2=3,634.54/2=1,817.27 metric tons. The fourth is true.
Answer: Fourth option: The average increase in the level of CO2 emissions per year from years 8 to 10 is 1,817.27 metric tons.
