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Zarrin [17]
3 years ago
6

What is 10x19-5+8=??

Mathematics
2 answers:
kakasveta [241]3 years ago
6 0
The answer's 193.. I've worked with these problems many times throughout the school years.. I worked it out in paper :)
ZanzabumX [31]3 years ago
5 0
The answer would be 193 because first u multiply 19 and 10 and then subtract 5 which is 185 and finally add 8 which is 193. 
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Estimate 726 Times 5
tester [92]

It's too easy just to calculate the actual value:

726 × 5 = 726 × 10/2 = 7260/2 = 3630

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You might estimate the value as 700 × 5 = 3500. You might estimate that to be low by 26/700 ≈ 4%, so about 140.

5 0
3 years ago
How many solutions does it have?<br> 3x+4 = 3x+4
MrRa [10]

Answer:

it has no solution.......

answer will be 3x+4 = 3x+4 i.e, 0=0 ,so

but if 3x+4 = 0 , x= -4/3 . Its a linear equation and has only one solution

3 0
2 years ago
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A carrot has a volume of 200cubic centimeters and a mass of 80grams. Calculate its density.
valentinak56 [21]
Density=m/V
m=80 gr
V=200cm^3
Density=80gr/200cm^3
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4 0
2 years ago
Compute the flux H F of F(x,y) = hxy, x − yi across the boundary of the square given by −1 ≤ x ≤ 1, −1 ≤ y ≤ 1.
Softa [21]

Answer:

4i.

Step-by-step explanation:

To find the flux through the square, we use the divergence theorem for the flux. So Flux of F(x,y) = ∫∫divF(x,y).dA

F(x,y) = hxy,x - yi

div(F(x,y)) = dF(x,y)/dx + dF(x,y)dy = dhxy/dx + d(x - yi)/dy = hy - i

So, ∫∫divF(x,y).dA = ∫∫(hy - i).dA

= ∫∫(hy - i).dxdy

= ∫∫hydxdy - ∫∫idxdy

Since we are integrating along the boundary of the square given by −1 ≤ x ≤ 1, −1 ≤ y ≤ 1, then

∫∫divF(x,y).dA = ∫₋₁¹∫₋₁¹hydxdy - ∫₋₁¹∫₋₁¹idxdy

= h∫₋₁¹{y²/2}¹₋₁dx - i∫₋₁¹[y]₋₁¹dx

= h∫₋₁¹{1²/2 - (-1)/2²}dx - i∫₋₁¹[1 - (-1)]dx

= h∫₋₁¹{1/2 - 1)/2}dx - i∫₋₁¹[1 + 1)]dx

= 0 - i∫₋₁¹2dx

= - 2i[x]₋₁¹

= 2i[1 - (-1)]

= 2i[1 + 1]

= 2i(2)

= 4i  

7 0
3 years ago
A simple random sample of electronic components wil be selected to test for the mean lifetime in hours. Assume that component li
Serjik [45]

Answer:

189 components must be sampled.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.99}{2} = 0.005

Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

That is z with a pvalue of 1 - 0.005 = 0.995, so Z = 2.575.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

Assume that component lifetimes are normally distributed with population standard deviation of 16 hours.

This means that \sigma = 16

How many components must be sampled so that a 99% confidence interval will have margin of error of 3 hours?

n components must be sampled.

n is found when M = 3. So

M = z\frac{\sigma}{\sqrt{n}}

3 = 2.575\frac{16}{\sqrt{n}}

3\sqrt{n} = 2.575*16

\sqrt{n} = \frac{2.575*16}{3}

(\sqrt{n})^2 = (\frac{2.575*16}{3})^2

n = 188.6

Rounding up:

189 components must be sampled.

4 0
3 years ago
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