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Lena [83]
3 years ago
8

Find all roots x^5-2x^3-8x=0

Mathematics
1 answer:
kobusy [5.1K]3 years ago
7 0
X^5 - 2 x^3 - 8 x=0x (x - 2) (x + 2) (x^2 + 2) = 0
x - 2 = 0 or x = 0 or x + 2 = 0 or x^2 + 2 = 0
x = 2 or x = 0 or x = - 2 or x^2 = - 2
x^2 = - 2 has no solution since for all x on the real line, x^2 >= 0 and - 2 < 0

Ans : x = 2 or x = 0 or x = - 2
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8. Jay drove 180 miles in 3 hours. Max drove 244 miles in 4 hours. Which of the following is true? (Show your
lyudmila [28]
The answer is B. Max drove faster than Jay.

180/3= 60
Jay drives 60 miles per hour

244/4= 61
Max drives 61 miles per hour
3 0
3 years ago
Property of multiplication<br>aa=169
kenny6666 [7]

aa is the same as a^2

a^2 = 169

a = SQRT(169)

a = 13

8 0
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Andre45 [30]

Answer:

1/4

Step-by-step explanation:

5 0
4 years ago
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Two students from a group of eight boys and 12 girls are sent to represent the school in a parade. If the students are chosen at
kari74 [83]

Answer:

Step-by-step explanation:

* Lets explain how to find the probability of an event  

- The probability of an Event = Number of favorable outcomes ÷ Total

 number of possible outcomes

- P(A) = n(E) ÷ n(S) , where

# P(A) means finding the probability of an event A  

# n(E) means the number of favorable outcomes of an event

# n(S) means set of all possible outcomes of an event

- Probability of event not happened = 1 - P(A)

- P(A and B) = P(A) . P(B)

* Lets solve the problem

- There is a group of students

- There are 8 boys and 12 girls in the group

∴ There are 8 + 12 = 20 students in the group

- The students are sent to represent the school in a parade

- Two students are chosen at random

∴ P(S) = 20

- The students that chosen are not both girls

∴ The probability of not girls = 1 - P(girls)

∵ The were 20 students in the group

∵ The number of girls in the group was 12

∴ The probability of chosen a first girl = 12/20

∵ One girl was chosen, then the number of girls for the second

  choice is less by 1 and the total also less by 1

∴ The were 19 students in the group

∵ The number of girls in the group was 11

∴ The probability of chosen a second girl = 11/19

- The probability of both girls is P(1st girle) . P(2nd girl)

∴ The probability of both girls = (12/20) × (11/19) = 33/95

- To find the probability of both not girls is 1 - P(both girls)

∴ P(not both girls) = 1 - (33/95) = 62/95

* The probability that the students chosen are not both girls is 62/95

3 0
3 years ago
Read 2 more answers
In a class of 40 students, everyone has either a pierced nose or a pierced ear. The professor asks everyone with a pierced nose
ladessa [460]

Answer:3

Step-by-step explanation:

Given

There are total 40 students in a class

No of students with Pierced Nose n(N)=7

No of students with Pierced ear n(E)=36

and we know using sets

n\left ( N\cup E\right )=n\left ( E\right )+n\left ( N\right )-n\left ( N\cap E\right )

where n\left ( N\cup E\right )=Students either nose or ear Pierced

n\left ( N\cap E\right )=no of students having both nose and ear pierced

40=7+36-n\left ( N\cap E\right )

n\left ( N\cap E\right )=43-40=3

3 0
4 years ago
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