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3 years ago

8

Find all roots x^5-2x^3-8x=0

1 answer:

kobusy [5.1K]3 years ago

7 0

X^5 - 2 x^3 - 8 x=0x (x - 2) (x + 2) (x^2 + 2) = 0
x - 2 = 0 or x = 0 or x + 2 = 0 or x^2 + 2 = 0
x = 2 or x = 0 or x = - 2 or x^2 = - 2
x^2 = - 2 has no solution since for all x on the real line, x^2 >= 0 and - 2 < 0

Ans : x = 2 or x = 0 or x = - 2

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PLS HELP Question 3

nikdorinn [45]

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This theorem states that a pair of vertical angles that are formed will always be congruent.
Number 1 description matches this theorem.

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This states that all three interior angles of a triangle equals 180 degrees.
Number 2 description matches this theorem.

<h3>What is the Corresponding Angles Postulate?</h3>

This states that the corresponding angles formed, when a transversal cuts two parallel lines, are congruent.
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This states that the same-side interior angles formed, when a transversal cuts two parallel lines, are congruent.
Number 8 description matches this theorem.

<h3>What is the Isosceles Triangle Theorem?</h3>

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Number 3 description matches this theorem.

<h3>What is the Alternate Exterior Angles Theorem?</h3>

This states that the alternate exterior angles formed, when a transversal cuts two parallel lines, are congruent.

Number 7 description matches this theorem.

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Number 4 description matches this theorem.

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Learn more about Angles Theorem on:

brainly.com/question/24756010

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3 years ago

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GREYUIT [131]

Answer

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Step-by-step explanation:

0.5454

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3 years ago

A biologist observed that a certain bacterial colony obeys the population growth law and that the colony triples every 4 hours.

MrRa [10]

Answer:

a) $P(t) = 2e^{0.275t}$

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Step-by-step explanation:

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In which P(t) is the population after t hours, $P_{0}$ is the initial population and r is the growth rate, as a decimal.

In this problem, we have that:

The colony occupied 2 square centimeters initially, so $P_{0} = 2$

The colony triples every 4 hours. So

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(a) An expression for the size P(t) of the colony at any time t.

We have to find the value of r. We can do this by using the P(4) equation.

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$e^{4r} = 3$

Applying ln to both sides, we get:

$4r = 1.1$

$r = 0.275$

So

$P(t) = 2e^{0.275t}$

(b) The area occupied by the colony after 12 hours.

$P(t) = 2e^{0.275t}$

$P(12) = 2e^{0.275*12}$

$P(12) = 54.225$

(c) The doubling time for the colony?

t when $P(t) = 2P_{0} = 2*2 = 4$ .

$P(t) = 2e^{0.275t}$

$4 = 2e^{0.275t}$

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