3.70 and 3.700 are some examples to get you started.
Let s represent the length of any one side of the original square. The longer side of the resulting rectangle is s + 9 and the shorter side s - 2.
The area of this rectangle is (s+9)(s-2) = 60 in^2.
This is a quadratic equation and can be solved using various methods. Let's rewrite this equation in standard form: s^2 + 7s - 18 = 60, or:
s^2 + 7s - 78 = 0. This factors as follows: (s+13)(s-6)=0, so that s = -13 and s= 6. Discard s = -13, since the side length cannot be negative. Then s = 6, and the area of the original square was 36 in^2.
Answer:
Whelan
Step-by-step explanation:
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The triangles formed by the path of the ball and the wall in the given diagram are similar triangles.
<h3>Correct Response;</h3>
The point on the wall she should aim is; <u>A. 7.8 feet away from point B</u>
<h3 /><h3>Method by which the above value is obtained;</h3>
The possible diagram in the question is attached
Let <em>x</em> represent the distance from point <em>B</em> where the ball lands.
ΔCDE is similar to ΔABE, by Angle-Angle similarity postulate.
By trigonometric ratio, the tangent of the angles ∠CDE and ∠BAE are;


tan(∠CDE) = tan(∠BAE)
Therefore;

Which gives;
16 × (20 - x) = 25·x
320 = 41·x
x = 320 ÷ 41 ≈ 7.8
The point on the wall she should aim if she's standing at point <em>A</em> is therefore;
- <u>A, 7.8 feet away from point </u><u><em>B</em></u>
Learn more about trigonometric ratios here:
brainly.com/question/4326804