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Verdich [7]
3 years ago
6

Determine LCM and HCF of 72 and 108 by prime factorisation​

Mathematics
1 answer:
Morgarella [4.7K]3 years ago
6 0

Answer:

8x9 and 12x9

Step-by-step explanation:

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Simplify the expression 4x+2-1/2x
oksano4ka [1.4K]

answer 41x

Step-by-step

6 0
3 years ago
In order to unlock the mystery window, you must enter a 3 digit code. You are given these following: -The number can be divided
liraira [26]
343 or how to solve LCM OR GCF Since 1 divides into everything, then the greatest common factor in this case is just 1. When 1 is the GCF, the numbers are said to be "relatively" prime; that is, they are prime, relative to each other. Then the GCF is 1 and the LCM is 2 × 2 × 2 × 3 = 24.

I can’t seem to figure it out so sorry but example on how to find it ^
4 0
3 years ago
Suppose the weights of the Boxers at this club are Normally distributed with a mean of 166 pounds and a standard deviation of 5.
lesya [120]

Answer:

0.1994 is the required probability.      

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 166 pounds

Standard Deviation, σ = 5.3 pounds

Sample size, n = 20

We are given that the distribution of weights is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

Standard error due to sampling =

=\dfrac{\sigma}{\sqrt{n}} = \dfrac{5.3}{\sqrt{20}} = 1.1851

P(sample of 20 boxers is more than 167 pounds)

P( x > 167) = P( z > \displaystyle\frac{167 - 166}{1.1851}) = P(z > 0.8438)

= 1 - P(z \leq 0.8438)

Calculation the value from standard normal z table, we have,  

P(x > 167) = 1 - 0.8006= 0.1994 = 19.94\%

0.1994 is the probability that the mean weight of a random sample of 20 boxers is more than 167 pounds

3 0
3 years ago
What is the value of x? What is the value of x?
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5 0
3 years ago
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Please answer I will make you Brainliest if it's right How do I do this step by step??
Sav [38]

Answer:

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3 0
3 years ago
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