The answer is A.
He ran for six (6) miles every day. 4 in the morning and 2 at night = 6 per day.
He did this for four (4) days. The way to figure this would be to go 6 * 4. This equals 24 miles.
Go back a few steps (punny!).
So days multiplied by how many miles he ran a day which is calculated by miles in morning added to miles at night.
days*(miles per morning + miles per night)
days=4
miles per morning=4
miles per night = 2
4 * (4+2)
Calculating this out....
4 * (4+2)
(4+2 = 6)
4 * 6 = 24.
So A is the answer.
First you know that at 6 it was 75 degrees. Now it’s noon and the temperature is 18 degrees warmer. So when you add 75 and 18 you get 93 degrees. When the storm rolls in at 4 it says that your temperature dropped 21 degrees. So you need to subtract 21 from 93 (93-21) which will get you at 72 degrees at 4pm
B+c is 16
16 + 25 Is 41
I don't know d sorry
Answer:
100 students should be surveyed in order to cut the width of the interval down from 3 hours to 1.5 hours
Step-by-step explanation:
Given that a 95% confidence interval, based upon a sample of size 25, for the mean number of hours of sleep that college students get per night was 5 to 8 hours.
Confidence interval = (5,8)
This implies that mean = 6.5 and margin of error = 1.5
i.e. 
If the interval width to be cut into half then the
New confidence interval = (5.75, 7.25)
Margin of error = 0.75
This is possible only when new n= 100
Hence sample size should be increased to 100
100 students should be surveyed in order to cut the width of the interval down from 3 hours to 1.5 hours
Answer: 1: row 3
2: Row 2
3: 6 and 10
Step-by-step explanation:I just did it
