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3 years ago

Which of the following sets of ordered pairs represents a relation that is not a function?

Mathematics

1 answer:

timama [110]3 years ago

6 0

D, because the domain 8 is repeating therefore it isn’t a function

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1. Evaluate the function below for the given input value.

svetlana [45]

Answer:

$f(2) = 4(2) - 6$

$f(2) = 8 - 6$

$f(2) = 2$

Hope it helpz

5 0

4 years ago

BRAINLIEST PLUS 100 POINTS

Anna35 [415]

Since it’s in percents, put the percent over 100 as a fraction and simplify them. For percents that aren’t given, add the rest and subtract it from 100 and then place it as a fraction over 100

4 0

4 years ago

2x - y = 5 x + 3y = 7 What is the value of the system determinant?

PSYCHO15rus [73]

2x - y = 5
x + 3y = 7

I'm assuming you mean the coefficient matrix.
$\left[\begin{array}{ccc}2&-1\\1&3\end{array}\right] =(2)(3)-(-1)(1)=6+1=7$

8 0

3 years ago

Read 2 more answers

Given that events A and B are independent with P(A)=0.24P(A)=0.24 and P(B|A)=0.85P(B∣A)=0.85, determine the value of P(B)P(B), r

NemiM [27]

Answer:

P(B) = 0.85

Step-by-step explanation:

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

$P(A) = 0.24, P(B|A) = 0.85$

These events are independent.

This means that $P(A \cap B) = P(A)*P(B)$ . So

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

$P(B|A) = \frac{P(A)*P(B)}{P(A)}$

$P(B|A) = P(B)$

$P(B) = 0.85$

5 0

3 years ago

A circle has a radius of 3. An arc in this circle has a central angle of 60°.

MArishka [77]

Answer:

Step-by-step explanation:

s = (∅/360) * (2πr)

s = (60/360) * (2π*3)

s = (1/6) * (6π)

s = π

8 0

3 years ago