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2 years ago

9

What is the square of 0.81?

2 answers:

PilotLPTM [1.2K]2 years ago

8 0

Answer:

<h2><u><em>0.9 or 9/10</em></u></h2>

Step-by-step explanation:

what is the square of 0.81?

0.9

The square root of 0.81 is equal to 0.9 or 9/10

--------------

check

0.9 * 0.9 = 0.81

the answer is good

uysha [10]2 years ago

7 0

Answer:

0.6561

Step-by-step explanation:

i think i could be wrong if am right brainliest

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a homework assignment included 40 multiple choice questions Sabrina completed 65% of her assignment in David completed 4/5 of hi

bazaltina [42]

Answer:

6 or -6

Step-by-step explanation:

65% of 40=26
4/5 of 40=32
32-26=6
(or if you start with 26)
26-32=-6

7 0

2 years ago

Read 2 more answers

the formula y-y1 =m(x-x1) is the pot slope form of the equation of a line where m is the slope of the line and(x,y) and (x1,y1)

oksano4ka [1.4K]

$\bf \begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&&(~{{ 4}} &,&{{ -2}}~) 
% (c,d)
&&(~{{ 5}} &,&{{ 0}}~)
\end{array}
\\\\\\
% slope = m
slope = {{ m}}\implies 
\cfrac{\stackrel{rise}{{{ y_2}}-{{ y_1}}}}{\stackrel{run}{{{ x_2}}-{{ x_1}}}}\implies \cfrac{5-(-2)}{0-4}\implies \cfrac{5+2}{0-4}\implies -\cfrac{7}{4}$

$\bf \stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-(-2)=-\cfrac{7}{4}(x-4)
\\\\\\
y+2=-\cfrac{7}{4}(x-4)\implies y+2=-\cfrac{7}{4}x+7\implies y=-\cfrac{7}{4}x+9$

6 0

3 years ago

Simplify each ratio 1. $8 to 62 cents 2. 14 inches to 2 yards 3. 5 days to 40 hours 4. Ratio of dogs to cats at the kennel if th

Vika [28.1K]

Answer:9

Step-by-step explanation:

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3 years ago

What is the sum of an infinite geometric series if the first term is 81 and the common ratio is 2⁄3?

Marrrta [24]

C

the sum to infinity of a geometric series = $\frac{a}{1-r}$

where a is the first term and r the common ratio

= $\frac{81}{\frac{1}{3} }$ = 81 × 3 = 243

4 0

3 years ago

Find a solution of the quadratic equation.6x squared + 7x + 2 =0

worty [1.4K]

Given the equation:

$6x^2+7x+2=0$

We will use the following rule to find the solution to the equation:

$x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}$

From the given equation: a = 6, b = 7, c = 2

So,

$\begin{gathered} x=\frac{-7\pm\sqrt[]{7^2-4\cdot6\cdot2}}{2\cdot6}=\frac{-7\pm\sqrt[]{1}}{12}=\frac{-7\pm1}{12} \\ x=\frac{-7-1}{12}=-\frac{8}{12}=-\frac{2}{3} \\ or,x=\frac{-7+1}{12}=-\frac{6}{12}=-\frac{1}{2} \end{gathered}$

So, the answer will be option B) x = -1/2, -2/3

5 0

1 year ago