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tatiyna
4 years ago
11

What is the length of the base of a right triangle with an area of 24 m² and a height of 4 m?

Mathematics
1 answer:
max2010maxim [7]4 years ago
7 0
Area of triangle = 1/2 × base × height
so,
24=1/2*base*4
base=12m
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Congruent triangles pls help
Harrizon [31]
Congruent triangle are the same shape and same size exactly
8 0
3 years ago
This is a polygon and I need help finding the missing angle ?
allsm [11]
First, you need to know that the total (degrees) of the interior angles is 360 because this is a quadrilateral.

The unnumbered angle is 109 degrees. We know this because the angle labeled 71 degrees and the unnumbered angle are supplementary. So you subtract 180 from 71 to get 109. 
180-71=109

To solve for x, we need to realize the other numbers playing into the angles' values. To make solving this easier, I'm gonna assign letters to the angles. 

(10x+6) is angle A. 

(13x-2) is angle B. 

(8x-1) is angle C.

and 109 (the one we solved) is angle D. 

We know that the total of the interior angles is 360, so we can add the 2 from angle B and the 1 from angle C to 360. This is because these numbers are subtracted from the other values. 
360+2+1=363

Now, we have to subtract the 6 from angle A from 363, because the 6 is added to the other values. 
363-6=357

Now we have to subtract 109 from 357 because you want to get the x's by themselves. Since you're solving for x. 
357-109=248

That leaves you with 248. Now you add all the x's up to get the total number of x's. You have 10x from angle A, 13x from angle B, and 8x from angle C. 
10x+13x+8x=31x

You get 31x. To get what x is, you divide 248 by 31. 
\frac{248}{31} =8

That equals 8. So now that you know that x equals 8, if you need to find the values of the angles, you just plug in the numbers into the formulas. 

(10(8))+6= 86
(13(8))-2=102
(8(8))-1=63
109

Check your work by plugging your answers in and seeing if they add up to 360. 
86+102+63+109=360

Which they should:)

So...
angle A= 86
angle B=102
angle C=63
angle D=109

and x=8



Hope this helped!!!
4 0
4 years ago
This is the image yall were asking for
Lubov Fominskaja [6]

Answer:

angle b+54 = 90 degrees

90 - 54 = b

36° = angle b

5 0
3 years ago
Read 2 more answers
Help me I have so many of these​
Doss [256]

Answer:

3/4

Step-by-step explanation:

dividing by a fraction is the same as multiplying by its reciprocal.

Therefore,

(1/2) / (2/3) = (1/2) * (2/3) = (3/4)

8 0
3 years ago
Suppose x=c1e−t+c2e3tx=c1e−t+c2e3t. Verify that x=c1e−t+c2e3tx=c1e−t+c2e3t is a solution to x′′−2x′−3x=0x′′−2x′−3x=0 by substitu
Harrizon [31]

The correct question is:

Suppose x = c1e^(-t) + c2e^(3t) a solution to x''- 2x - 3x = 0 by substituting it into the differential equation. (Enter the terms in the order given. Enter c1 as c1 and c2 as c2.)

Answer:

x = c1e^(-t) + c2e^(3t)

is a solution to the differential equation

x''- 2x' - 3x = 0

Step-by-step explanation:

We need to verify that

x = c1e^(-t) + c2e^(3t)

is a solution to the differential equation

x''- 2x' - 3x = 0

We differentiate

x = c1e^(-t) + c2e^(3t)

twice in succession, and substitute the values of x, x', and x'' into the differential equation

x''- 2x' - 3x = 0

and see if it is satisfied.

Let us do that.

x = c1e^(-t) + c2e^(3t)

x' = -c1e^(-t) + 3c2e^(3t)

x'' = c1e^(-t) + 9c2e^(3t)

Now,

x''- 2x' - 3x = [c1e^(-t) + 9c2e^(3t)] - 2[-c1e^(-t) + 3c2e^(3t)] - 3[c1e^(-t) + c2e^(3t)]

= (1 + 2 - 3)c1e^(-t) + (9 - 6 - 3)c2e^(3t)

= 0

Therefore, the differential equation is satisfied, and hence, x is a solution.

4 0
3 years ago
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