Area of triangle: 3m
Area of rectangle: 24m
Area of semi-circle: 6.28m
For this case we have the following equation:
We must find the value of "x":
We apply cube root on both sides of the equation to eliminate the exponent:
![x = \sqrt [3] {375}](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%20%5B3%5D%20%7B375%7D)
We can write 375 as 
So:
![x = \sqrt [3] {5 ^ 3 * 3}\\x = 5 \sqrt [3] {3}](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%20%5B3%5D%20%7B5%20%5E%203%20%2A%203%7D%5C%5Cx%20%3D%205%20%5Csqrt%20%5B3%5D%20%7B3%7D)
Then, the correct options are:
![x = \sqrt [3] {375}\\x = 5 \sqrt [3] {3}](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%20%5B3%5D%20%7B375%7D%5C%5Cx%20%3D%205%20%5Csqrt%20%5B3%5D%20%7B3%7D)
Answer:
Option A and B
D1,..,d9 = 0,0,2,2,2,3,4,6,8 //there are 9 values, in ascending order
Q2 (median) = d5 = 2 //value in the middle
Q1 = (d2+d3) / 2 = (0+2)/2 = 1
(Q1 is middle value of d1,d2,d3,d4, but there is no middle element among four elements, that is why arithmetic mean is taken)
Q3 = (d7+d8) / 2 = (4+6)/2 = 5
interquantlie range = IQR = Q3 - Q1 = 5 -1 = 4
answer: 4
Answer:
2112 yards
Step-by-step explanation:
1.2 mi = 2112 yards
Answer:
The Trout will have to jump 49 cm in order to catch the insect
Step-by-step explanation:
Here, we want to calculate the distance the Trout has to jump in order to catch the Insect
To calculate this, we need to know the difference in the distances
From what we have, the Trout is 32 cm below the surface while the Insect is 17 cm above the surface of the lake
The difference in height which will represent the distance that the Trout has to jump to catch the insect will be ;
17 + 32 = 49 cm
