The average rate of change for the height of the plant measured in centimeters per day between day 0 and day 20 is 1.32 cm per day.
<h3>What is average height?</h3>
The average height is the ratio of change in height of the plant and the time taken taken for that change.
Given is the height of a plant in centimeters is modeled as a function of time, in days.
For day 0, the height is 18cm and the height for day 20 is 42 cm, then the average height change is
height per day = 42 - 18/ 20 -0
height per day = 1.2 cm/day
Thus, the average height of plant is 1.2 cm/day.
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Answers:
k = 13The smallest zero or root is x = -10
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Work Shown:
note: you can write "x^2" to mean "x squared"
f(x) = x^2+3x-10
f(x+5) = (x+5)^2+3(x+5)-10 ... replace every x with x+5
f(x+5) = (x^2+10x+25)+3(x+5)-10
f(x+5) = x^2+10x+25+3x+15-10
f(x+5) = x^2+13x+30
Compare this with x^2+kx+30 and we see that k = 13
Factor and solve the equation below
x^2+13x+30 = 0
(x+10)(x+3) = 0
x+10 = 0 or x+3 = 0
x = -10 or x = -3
The smallest zero is x = -10 as its the left-most value on a number line.
The March sales of Jazz records is an illustration of proportions, and the number of jazz records sold all year is 7x
<h3>How to determine the total number of sales?</h3>
The sales in March is given as:
Proportion = 1/7
Let the actual number of sales in the month of March be x, and the total sales in the year be y.
So, we have:
1/7 * y = x
Make y the subject
y =7x
Hence, the number of jazz records sold all year is 7x
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To calculate the volume of a sphere you must use the formula
v=4/3pir^3
The radius (r) is half of the diameter
r=13.5
v=4/3pi13.5^3
v=10305.99
Therefore the volume of the sports ball is 10306cm^3 (to the nearest tenth)
Answer:
Volume = 
Step-by-step explanation:
Given - Consider the solid S described below. The base of S is the triangular region with vertices (0, 0), (4, 0), and (0, 4). Cross-sections perpendicular to the x-axis are squares.
To find - Find the volume V of this solid.
Solution -
Given that,
The equation of the line with both x-intercept and y-intercept as 4 is -

⇒x + y = 4
⇒y = 4 - x
Now,
Volume = 
where
A(x) is the area of general cross-section.
It is given that,
Cross-sections perpendicular to the x-axis are squares.
So,
A(x) = (4 - x)²
As solid lies between x = 0 and x = 4
So,
The Volume becomes
Volume = 
= ![\int\limits^4_0 {[(4)^{2} + (x)^{2} - 8x] } \, dx](https://tex.z-dn.net/?f=%5Cint%5Climits%5E4_0%20%7B%5B%284%29%5E%7B2%7D%20%20%2B%20%28x%29%5E%7B2%7D%20-%208x%5D%20%7D%20%5C%2C%20dx)
= ![\int\limits^4_0 {[16 + x^{2} - 8x] } \, dx](https://tex.z-dn.net/?f=%5Cint%5Climits%5E4_0%20%7B%5B16%20%20%2B%20x%5E%7B2%7D%20-%208x%5D%20%7D%20%5C%2C%20dx)
= ![{[16 x + \frac{x^{3}}{3} - \frac{8x^{2} }{2} ] } ^4_0](https://tex.z-dn.net/?f=%7B%5B16%20x%20%20%2B%20%5Cfrac%7Bx%5E%7B3%7D%7D%7B3%7D%20%20-%20%5Cfrac%7B8x%5E%7B2%7D%20%7D%7B2%7D%20%5D%20%7D%20%5E4_0)
= ![{[16(4 - 0) + \frac{4^{3}}{3} - \frac{0^{3}}{3} - 4 [4^{2} - 0^{2}] ] }](https://tex.z-dn.net/?f=%7B%5B16%284%20-%200%29%20%20%2B%20%5Cfrac%7B4%5E%7B3%7D%7D%7B3%7D%20-%20%5Cfrac%7B0%5E%7B3%7D%7D%7B3%7D%20%20-%204%20%5B4%5E%7B2%7D%20-%200%5E%7B2%7D%5D%20%20%20%5D%20%7D)
= ![{[16(4) + \frac{64}{3} - 0 - 4 [16 - 0] ] }](https://tex.z-dn.net/?f=%7B%5B16%284%29%20%20%2B%20%5Cfrac%7B64%7D%7B3%7D%20-%200%20%20-%204%20%5B16%20-%200%5D%20%20%20%5D%20%7D)
= ![{[64 + \frac{64}{3} - 64 ] }](https://tex.z-dn.net/?f=%7B%5B64%20%20%2B%20%5Cfrac%7B64%7D%7B3%7D%20%20-%2064%20%20%5D%20%7D)
= 
⇒Volume = 