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4 years ago

Which of the following best explains why chemical equations are balanced?

Chemistry

2 answers:

Lesechka [4]4 years ago

5 0

The answer would be c

Norma-Jean [14]4 years ago

4 0

Answer:

c.) energy is transferred

Explanation:

The chemical equations are balanced because of the energy conservation principle that states that the total energy of an isolated system remains constant in all chemical reactions, whether you have an exothermic, endothermic or reversible reactions. A chemical reaction by itself is a matter of energy transfer, the combustion process in a lighter, for example, generates a flame that gives out energy in the form of light, heat, and sound.

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When a solution of 6m hcl is made from a stock of concentrated hcl by adding an equal volume of water, why is the concentration

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Answer:-

HCl is a volatile acid. It easily evaporates at room temperature. So the concentrated HCl which is supposed to be 12 M is no longer 12 M since some of the HCl has already escaped as vapor.

Hence when a solution of 6M HCl is made from a stock of concentrated HCl by adding an equal volume of water, the concentration of the solution is only an approximate concentration since the concentration of the stock concentrated solution is also approximate.

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3 years ago

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3 years ago

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4 years ago

Consider the acid-base neutralization reaction H2S(aq) + CN‒(aq) ⇌ HS‒(aq) + HCN(aq) For H2S, pKa = 7.0, and for HCN, pKa = 9.4.

zubka84 [21]

Answer:

Explanation:

To assess the strength of an acid or a base we need to consider the pKa or pKb. For an acid, the lower the pKa, the stronger the acid. For a base, the lower the pKb, the stronger the base.

Which of the following statements is FALSE?

(a) H₂S is a stronger acid than HCN. TRUE. The pKa of H₂S (7.0) is lower than the pKa of HCN (9.4).

(b) CN⁻ is a stronger base than HS⁻. TRUE. We can calculate the pKb of a base when we know the pKa of the conjugate acid using the following expression:

pKa + pKb = 14 ⇒ pKb = 14 - pka

The pKb of CN⁻ (4.6) is lower than the pKb of HS⁻(7.0) so it is a stronger base.

(c) At equilibrium, the equilibrium position favors the reactants. FALSE. In the reaction H₂S(aq) + CN⁻(aq) ⇌ HS⁻(aq) + HCN(aq), H₂S is the stronger acid and CN⁻ is the stronger base, so at the equilibrium the products are favored.

(d) At equilibrium, the equilibrium constant, Kc, is larger than 1. TRUE. Given the products are favored at the equilibrium, the equilibrium constant Kc is expected to be larger than 1 (the numerator is higher than the denominator).

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3 years ago