A sample of gas occupies a volume of 72.0 mL . As it expands, it does 141.2 J of work on its surroundings at a constant pressure
1 answer:
The final volume of the gas is 73.359 mL
<h3 />Given :
A sample gas has an initial volume of 72.0 mL
The work done = 141.2 J
Pressure = 783 torr
The objective is to determine the final volume of the gas.
Since, the process does 141.2 J of work on its surroundings at a constant pressure of 783 Torr. Then, the pressure is external.
Converting the external pressure to atm; we have
External Pressure P:
= 783 torr ×
= 1.03 atm
The work done W =
The change in volume ΔV=
ΔV =
ΔV =
ΔV = 0.001359 L
ΔV = 1.359 mL
The initial volume = 72.0 mL
The change in volume V is ΔV = V₂ - V₁
- V₂ = - ΔV - V₁
multiply both sides by (-), we have:
V₂ = ΔV + V₁
= 1.359 mL + 72.0 mL
= 73.359 mL
Therefore, the final volume of the gas is 73.359 mL .
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Answer:
8.32 s⁻¹
Explanation:
Given that:
The concentration of myosin = 25 pmol/L
R_max = 208 pmol/L/s
The objective is to determine the turnover number of the enzyme molecule myosin, which has a single active site.
In a single active site of enzyme is known to be a region where there is binding of between substrate molecules, thereafter undergoing chemical reaction.
The turnover number of the enzyme is said to be the number of these substrate molecule which binds together are being converted into products.
The turnover number of the enzyme molecule of myosin can be calculated by the expression:
⇒
= 8.32 s⁻¹