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Mademuasel [1]
4 years ago
15

The computer rendering of a mural in a town’s square uses the function represented in the table to define the outline of a mount

ain in the town’s logo, where x is the distance in feet from the edge of the mural and f(x) is the distance from the ground in feet. How can the point (12, 16) be explained? The highest point of the mountain defined by the function is 12 feet. The highest point of the mountain defined by the function is 16 feet. The width of the base of the mountain defined by the function is 12 feet. The width of the base of the mountain defined by the function is 16 feet.
Mathematics
2 answers:
I am Lyosha [343]4 years ago
7 0

Answer:

  none of the above.

  Please discuss this question with your teacher.

Step-by-step explanation:

The problem statement tells you that the appropriate interpretation of the point (12, 16) is that <em>the outline of the mountain on the mural is 16 feet from the ground at a point 12 feet from the edge of the mural</em>.

__

There is no information about the base of the mountain or its maximum height, so no conclusions can be drawn regarding those parameters.

Len [333]4 years ago
6 0

Answer: B The highest point of the mountain is defined by the function is 16 feet

Step-by-step explanation:

I got it right on Edge

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Andrej [43]

Answer:

A = [\frac{32}{3}]

Step-by-step explanation:

Given

y_1 = 2x - x^2

y_2 = 2x - 4

Required

Determine the area bounded by the curves

First, we need to determine their points of intersection

2x - x^2 = 2x - 4

Subtract 2x from both sides

-x^2 = -4

Multiply through by -1

x^2 = 4

Take square root of both sides

x = 2   or    x = -2

This Area is then calculated as thus

A = \int\limits^a_b {[y_1 - y_2]} \, dx

<em>Where a = 2 and b = -2</em>

Substitute values for y_1 and y_2

A = \int\limits^a_b {(2x - x^2) - (2x - 4)} \, dx

Open Brackets

A = \int\limits^a_b {2x - x^2 - 2x + 4} \, dx

Collect Like Terms

A = \int\limits^a_b {2x - 2x- x^2  + 4} \, dx

A = \int\limits^a_b {- x^2  + 4} \, dx

Integrate

A = [-\frac{x^{3}}{3} +4x](2,-2)

A = [-\frac{2^{3}}{3} +4(2)] - [-\frac{-2^{3}}{3} +4(-2)]

A = [-\frac{8}{3} +8] - [-\frac{-8}{3} -8]

A = [\frac{-8+ 24}{3}] - [\frac{8}{3} -8]

A = [\frac{-8+ 24}{3}] - [\frac{8-24}{3}]

A = [\frac{16}{3}] - [\frac{-16}{3}]

A = [\frac{16}{3}] + [\frac{16}{3}]

A = [\frac{16 + 16}{3}]

A = [\frac{32}{3}]

Hence, the Area is:

A = [\frac{32}{3}]

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Dahasolnce [82]

Using the expected value, it is found that the mean of the distribution equals $0.1.

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The probabilities of <u>each outcome</u> are:

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Thus, the mean is given by:

E(Y) = 0.0000001(1000000) + 0.9999999(0) = 0.1

Thus showing that the expected value is $0.1.

A similar problem is given at brainly.com/question/24855677

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Answer:

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