Answer:
0.0177 = 1.77% probability that the first defect is caused by the seventh component tested.
The expected number of components tested before a defective component is found is 50, with a variance of 0.0208.
Step-by-step explanation:
Assume that the probability of a defective computer component is 0.02. Components are randomly selected. Find the probability that the first defect is caused by the seventh component tested.
First six not defective, each with 0.98 probability.
7th defective, with 0.02 probability. So

0.0177 = 1.77% probability that the first defect is caused by the seventh component tested.
Find the expected number and variance of the number of components tested before a defective component is found.
Inverse binomial distribution, with 
Expected number before 1 defective(n = 1). So

Variance is:

The expected number of components tested before a defective component is found is 50, with a variance of 0.0208.
Answer:
Rectangle.
Round.
Arched.
Novelty.
Square.
Oval.
Octagon.
Sunburst.
Hope this is what you're looking for :)
Brainliest please
The most she can pay for the jacket is $375 (=600/(100%+60%)) assuming this is the cost of the jacket before it sewn with metallic threads and beads. A markup is a difference between the production cost and the selling price in order to cover the additional cost related to the product. Based on the data, she wants to keep the 60% for covering the cost.
The first five terms of the sequence are; 4,600, 4,550, 4,500, 4,450, 4,400 and the total predicted number of sold cars for the first year is 51,900 cars
<h3>Arithmetic sequence</h3>
- First month, a = 4,600 cars
- Common difference, d = -50 cars
First five terms;
a = 4,600
a + d = 4600 + (-50)
= 4600 - 50
= 4,550
a + 2d
= 4600 + 2(-50)
= 4600 - 100
= 4,500
a + 3d
= 4,600 + 3(-50)
= 4,600 - 150
= 4,450
a + 4d
= 4600 + 4(-50)
= 4,600 - 200
= 4,400
cars predicted for the twelfth month.
a + 11d
= 4600 + 11(-50)
= 4600 + 550
= 4,050
Total predicted number of sold cars for the first year:
Sn = n/2{2a + (n - 1)d }
= 12/2{2×4600 + (12-1)-50}
= 6{9200 + 11(-50)}
= 6(9,200 - 550)
= 6(8,650)
= 51,900 cars
Learn more about arithmetic sequence:
brainly.com/question/6561461
#SPJ1