All categories

4 years ago

Help plz it is only one question

Mathematics

1 answer:

Akimi4 [234]4 years ago

3 0

It would be 43.75% because

7÷16=0.4375
0.4375×100=43.75%

You might be interested in

Is this graph linear or exponential

barxatty [35]

Its a graph linear i believe

3 0

3 years ago

Working alone, shayna can harvest a field in 8 hours. John can harvest the same field in 16 hours. How long would it take them i

Alinara [238K]

(1/8)x + (1/16)x = 1
(2/16)x + (1/16)x = 1
(3/16)x = 1
x = 16/3 = 5.33333 hrs

7 0

3 years ago

Assume a simple random sample of 10 BMIs with a standard deviation of 1.186 is selected from a normally distributed population o

kirza4 [7]

Answer:

a) H0: $\sigma = 1.34$

H1: $\sigma \neq 1.34$

b) $df = n-1= 10-1=9$

And the critical values with $\alpha/2=0.005$ on each tail are:

$\chi_{\alpha/2}= 1.735, \chi_{1-\alpha/2}= 23.589$

c) $t=(10-1) [\frac{1.186}{1.34}]^2 =7.05$

d) For this case since the critical value is not higher or lower than the critical values we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not significantly different from 1.34

Step-by-step explanation:

Information provided

n = 10 sample size

s= 1.186 the sample deviation

$\sigma_o =1.34$ the value that we want to test

$p_v$ represent the p value for the test

t represent the statistic (chi square test)

$\alpha=0.01$ significance level

Part a

On this case we want to test if the true deviation is 1,34 or no, so the system of hypothesis are:

H0: $\sigma = 1.34$

H1: $\sigma \neq 1.34$

The statistic is given by:

$t=(n-1) [\frac{s}{\sigma_o}]^2$

Part b

The degrees of freedom are given by:

$df = n-1= 10-1=9$

And the critical values with $\alpha/2=0.005$ on each tail are:

$\chi_{\alpha/2}= 1.735, \chi_{1-\alpha/2}= 23.589$

Part c

Replacing the info we got:

$t=(10-1) [\frac{1.186}{1.34}]^2 =7.05$

Part d

For this case since the critical value is not higher or lower than the critical values we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not significantly different from 1.34

5 0

3 years ago

23,710 23,751,23,715

Hoochie [10]

23, 710, 23, 751, 23, 715 Least to greatest

23, 23, 23, 710, 715, 751

7 0

3 years ago

Make q the subject of the formula 2(q+p) = 1 + 5 q

CaHeK987 [17]

Answer:

q = 2/3p - 3

Step by step:

2q+2p = 1+5q
2q - 5q = -2p + 1
-3q = -2p + 1
q = 2/3p - 3

3 0

3 years ago