Remember
(ab)/(cd)=(a/c)(b/d)
and

1kg=1000g=1*10^3g
hmm, I estimate, 4 of them
x=number of attoms
mass of 1 times x=1*10^3
3.95*10^-22 times x=1*10^3
divide both sides by 3.95*10^-22
x=

=

=

a million has 9 zeroes
so 24 zeroes is alot that is a <span>septillion, so there are 2.5316 septillion uranium atoms in 1kg
a. 4
b. underestimate
</span>
Answer:
V = 32/3 pi
Step-by-step explanation:
The volume of a sphere is given by
V= 4/3 pi r^3
We know the radius is 2
V = 4/3 pi (2)^3
V = 4/3 pi (8)
V = 32/3 pi
Answer:
A sample size of 35 is needed.
Step-by-step explanation:
We have that to find our
level, that is the subtraction of 1 by the confidence interval divided by 2. So:

Now, we have to find z in the Ztable as such z has a pvalue of
.
So it is z with a pvalue of
, so 
Now, find the width W as such

In which
is the standard deviation of the population and n is the size of the sample.
How large must the sample size be if the width of the 95% interval for mu is to be 1.0:
We need to find n for which W = 1.
We have that
, then
. So





Rounding up
A sample size of 35 is needed.
The answer is -9i , 9i
x^2+81=0
x^2=-81
x=√-81
=9i,-9i
Ratio of amount of change to original shown as a percent.