Let the speed off the walk way be x and speed of the walkway be y
x+y=6....i
x-y=2....ii
adding the above equation we get:
2x=8
thus
x=4 ft/s
and
y=6-4=2 ft/s
thus the speed off the walk way is 4 ft/s
the speed of the moving walkway is 2 ft/s
(3*2)(10^2 * 10^3) = 6*10^5
Answer: 49 in^2
Step-by-step explanation:
Trapezoid area formula = (a+b/2) x h
So...
(5+9/2) x 7
= 49 in^2
Divide both sides by 2 to get x>3
