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Nat2105 [25]
3 years ago
15

Question 3

Mathematics
1 answer:
Triss [41]3 years ago
8 0

Answer: h=3.1\ m

Step-by-step explanation:

The missing figure is attached.

For this exercise it is important to remember that the volume of a rectangular prism can be calculated using the following formula:

V=lwh

Where "V" is the volume, "l" is the length, "w" is the width and "h" is the height of the rectangular prism.

In this case, as you can identify in the figure attached, the length and the width of this rectangular prism are:

l=18\ m\\\\w=6\ m

And you already know that:

V=334.8\ m^3

Therefore, knowing those values, you can substitute them into the formula and then solve for "h" in order to find its value.

This is:

334.8\ m^3=(18\ m)(6\ m)h\\\\\frac{334.8\ m^3}{108\ m^2}=h\\\\h=3.1\ m

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Leni [432]

Answer:

29

Step-by-step explanation:

(x+12) + 100 + x = 180

           2x + 112 = 180

Subtract 112 from both sides

                    2x = 58

Divide 2 from both sides

                      x = 29

3 0
3 years ago
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mr Goodwill [35]

Answer:

Step-by-step explanation:

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3 0
2 years ago
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If D is the center of the circle below and AC measures 48, what is the measure of ABC
dimulka [17.4K]

Answer:

24

Step-by-step explanation:

How do we know that a circle must complete up to 180, then we have to:

180 - 48 = 132

Now knowing this distance we can also know the other, starting from the same concept, in addition to what the circle below is like, a semicircle refers to so we divide by 2:

(180-132) / 2 = 24

Therefore the answer is 24.

We can also do it ABC is half of ADC. So ABC = 48/2 = 24

4 0
3 years ago
Use exterior angles to show that the angle sum of quadrilateral PQRS is 360°.​
Shkiper50 [21]

Answer:

I don't really know but one triangle is 180 degrees so two added together is 360 degrees...

but ohh I remembered

a=c+d (since a+b=180 and c+d+b=180)

e=g+h (since e+f=180 and g+h+f= 180)

and the fact is that c+d+g+h+b+f=the angle sum of quadrilateral PQRS

a+e+b+f= the angle sum of quadrilateral PQRS (by substitutions)

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8 0
3 years ago
Help please with algebra problem
Strike441 [17]
Number of weekend minutes used: x
Number of weekday minutes used: y

This month Nick was billed for 643 minutes:
(1) x+y=643

The charge for these minutes was $35.44
Telephone company charges $0.04 per minute for weekend calls (x)
and $0.08 per minute for calls made on weekdays (y)
(2) 0.04x+0.08y=35.44

We have a system of 2 equations and 2 unkowns:
(1) x+y=643
(2) 0.04x+0.08y=35.44

Using the method of substitution
Isolating x from the first equation:
(1) x+y-y=643-y
(3) x=643-y

Replacing x by 643-y in the second equation
(2) 0.04x+0.08y=35.44
0.04(643-y)+0.08y=35.44
25.72-0.04y+0.08y=35.44
0.04y+25.72=35.44

Solving for y:
0.04y+25.72-25.72=35.44-25.72
0.04y=9.72

Dividing both sides of the equation by 0.04:
0.04y/0.04=9.72/0.04
y=243

Replacing y by 243 in the equation (3)
(3) x=643-y
x=643-243
x=400


Answers:
The number of weekends minutes used was 400
The number of weekdays minutes used was 243
6 0
3 years ago
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