Expand then simplify: 12(2p-3)
1 answer:
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Answer:
<em>The test statistic value t = 1.64 < 2.0086 at 0.05 level of significance</em>
<em>Null hypothesis is accepted</em>
<em>The mean portfolio value for all senior citizen shareholders in this region might not be the same as the mean value reported for their counterparts across the nation </em>
<em></em>
Step-by-step explanation:
<u><em>Step(i)</em></u>:-
Given mean of the population (μ) = $183,000
Given mean of the sample (x⁻) = $198,000
Given standard deviation of the sample (S) = $65,000.
Mean of the sample size 'n' = 51
level of significance α = 0.05
<u><em>Step(ii):</em></u>-
<u><em>Null hypothesis : H₀</em></u> : There is no significance difference between the means
<em>Alternative Hypothesis :H₁: </em>There is significance difference between the means
<em>Test statistic</em>
<em> </em><em></em>
<em> </em><em></em>
<em> t = 1.64</em>
<u><em>Step(iii)</em></u>
<em>Degrees of freedom ν = n-1 = 51-1 =50</em>
<em>t₀.₀₅ = 2.0086</em>
<em>The calculated value t = 1.64 < 2.0086 at 0.05 level of significance</em>
<em>Null hypothesis is accepted </em>
<u><em>Final answer:-</em></u>
<em>There is no significance difference between the means</em>
<em> The mean portfolio value for all senior citizen shareholders in this region might not be the same as the mean value reported for their counterparts across the nation</em>