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4 years ago

9

Expand then simplify: 12(2p-3)

1 answer:

avanturin [10]4 years ago

7 0

Answer:

expanding ends in the simplest form: 24p-36

Step-by-step explanation:

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A car enters an interstate highway 20 mi north of a city. The car travels north at an average speed of 58 mph. Which equation mo

HACTEHA [7]

The answer would be 20 d = h + 58

3 0

3 years ago

A study claims that the mean age of online dating service users is 40 years. Some researchers think this is not accurate and wan

Mademuasel [1]

Answer: $H_0:\mu=40$

$H_0:\neq40$

Step-by-step explanation:

A null hypothesis is a hypothesis where a researcher generally try to disprove, it says that there is no statistically significant relationship between the two variables .
An alternative hypothesis says that there is a statistical significance between two variables.

Claim 1. : Mean age of online dating service users is 40 years.

i.e. $\mu=40$ , since it has equals sign so we take this as null hypothesis.

Claim 2. : Mean age of online dating service users is not 40 years.

$\mu\neq40$

⇒ Null Hypothesis : $H_0:\mu=40$

Alternative hypothesis : $H_0:\neq40$

5 0

3 years ago

A point is an exact location that has no size or dimension. True or False?

Zarrin [17]

It's true because a pint is used to locate co-ordinates and has no size or dimension

5 0

3 years ago

Read 2 more answers

Jack drove 41 1/2 miles. He used 1 1/4 gallons of gasoline . What is the unit rate for miles per gallon ?

olasank [31]

Answer:

How do I have the same problem as a high schooler when im in 6th grade

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3 years ago

Compound interest In Exercise,$3000 is invested in an account at interest rate r,compounded continuously.Find the time required

xenn [34]

Answer:

(a) 8.15

(b) 12.92

Step-by-step explanation:

Given: P = $3000, r = 0.085

$A = Pe^{rt}$

Where

A is the Amount

P is the Principal

r is the rate

t is the time

(a) For the amount to double, A = 2 × P

A = 2 × $3000

A = $6000

$6000 = 3000e^{0.085t}$

$\frac{6000}{3000} = e^{0.085t}$

$2 = e^{0.085t}$

Take $log_{e}$ of both sides

$log_{e}2 = log_{e}e^{0.085t}$

But $log_{e}e = 1$

∴ $ln2 = 0.085t$

$t = \frac{ln2}{0.085}$

$t = \frac{0.693}{0.085}$

t = 8.15

(b) For the amount to double, A = 3 × P

A = 3 × $3000

A = $9000

$9000 = 3000e^{0.085t}$

$\frac{9000}{3000} = e^{0.085t}$

$3 = e^{0.085t}$

Take $log_{e}$ of both sides

$log_{e}3 = log_{e}e^{0.085t}$

But $log_{e}e = 1$

∴ $ln3 = 0.085t$

$t = \frac{ln3}{0.085}$

$t = \frac{1.0986}{0.085}$

t = 12.92

5 0

3 years ago