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pashok25 [27]
2 years ago
10

I need only part b help me please

Mathematics
1 answer:
FrozenT [24]2 years ago
8 0
Your mom should know the answer just go ask her! But it is 205 plus 980-13057 which equals to 20
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A single die is rolled one time. Find the probability of rolling a number greater than 4 or less than 3
Tomtit [17]
You have a 2/6 chance of rolling <span>a number greater than 4 or less than 3 which reduces to 1/3
2/6 = 1/3</span>
8 0
3 years ago
What math property is this example?:<br><br>5+(-5)=0​
belka [17]

Answer:

Additive Identity Property: The sum of any number and zero is the original number. For example 5 + 0 = 5

Step-by-step explanation:

Additive Identity Property: The sum of any number and zero is the original number. For example 5 + 0 = 5

6 0
3 years ago
Find the coordinates of the point 7/10 of the way from A to B. a=(-3,-6) b=(12,4)
Artemon [7]

Answer:

The coordinates of M are x = \frac{15}{2} and y = 1.

Step-by-step explanation:

Let be A = (-3,-6) and B = (12, 4) endpoints of segment AB and M a point located 7/10 the way from A to B. Vectorially, we get this formula:

\overrightarrow {AM} = \frac{7}{10}\cdot \overrightarrow {AB}

\vec M - \vec A = \frac{7}{10}\cdot (\vec B - \vec A)

By Linear Algebra we get the location of M:

\vec M = \vec A + \frac{7}{10}\cdot (\vec B - \vec A)

\vec M = \vec A +\frac{7}{10}\cdot \vec B - \frac{7}{10}\cdot \vec A

\vec M = \frac{3}{10}\cdot \vec A + \frac{7}{10}\cdot  \vec B

If we know that \vec A = (-3,-6) and \vec B = (12, 4), then:

\vec M = \frac{3}{10}\cdot (-3,-6)+\frac{7}{10}\cdot (12,4)

\vec M = \left(-\frac{9}{10},-\frac{9}{5}  \right)+\left(\frac{42}{5} ,\frac{14}{5} \right)

\vec M =\left(-\frac{9}{10}+\frac{42}{5} ,-\frac{9}{5}+\frac{14}{5}   \right)

\vec M = \left(\frac{15}{2} ,1\right)

The coordinates of M are x = \frac{15}{2} and y = 1.

6 0
3 years ago
Name three different ways you can represent a group of equivalent ratios.
KonstantinChe [14]
One way is by using the same number

3 0
3 years ago
Read 2 more answers
FIND THE SUM:<br> (6x^2-2x-3)+(x^2-3x+1)<br><br> 1.6x^2+6x+3<br> 2.7x^2+5x+2<br> 3.7x^2-5x-2
Butoxors [25]

8x^2-5x-2

method

open bracket

6x^2-2x-3+x^2-3x+1

collect like terms

6x^2+2x^2-3-3x+1

8x^2-3-3x+1

again collect like terms

8x^2-2x-3x-3+1

8x^2-5x-3+1. (-×-=+ addition but keeping sign minus

8x-5x-2. (-×+=-)

5 0
3 years ago
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