Answer:
b
Step-by-step explanation:
im 50% sure this write dont blame me man
Given:
Uniform distribution of length of classes between 45.0 to 55.0 minutes.
To determine the probability of selecting a class that runs between 51.5 to 51.75 minutes, find the median of the given upper and lower limit first:
45+55/2 = 50
So the highest number of instances is 50-minute class. If the probability of 50 is 0.5, then the probability of length of class between 51.5 to 51.75 minutes is near 0.5, approximately 0.45. <span />
You divide 18 with 3 and is going to equal 6 so that should be your constant proportionality
Answer:
y = -2x -3
Step-by-step explanation:
- the altitude trough F is a perpendicular line to the line DE
- find slope of line DE
D ( x2 = -5, y2 = -1); E (x1 = 3, y1 = 3)
slope m = (y2-y1) / (x2-x1) = (-1-3) / (-5-3) = -4/ -8 = 1/2
-find equation of the altitude trough F
lines that are perpendicular have the slope negative reciprocal (negative reciprocal of 1/2 is -2)
y= -2x +b , for point F(1, -5)
-5 = -2*1 +b, add 2 to both sides
-5 +2 = b, combine like terms
-3 =b
equation of the altitude trough F is y = -2x -3
We have that
<span>[6x+5]=1+2*(3x+2)
[6x+5]=1+2*3x+2 --------> is not correct ------->1+ 2*(3x+2)=1+2*3x+2*2
then
</span>[6x+5]=1+6x+4---------------> [6x+5]=[6x+5]
<span>this equation is an identity, all real numbers are solutions.</span>
