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emmasim [6.3K]
3 years ago
9

Which of the following numbers is a multiple of 6?

Mathematics
2 answers:
kirill [66]3 years ago
5 0
The answer is D. 882! This is because the number must be divisible by both 2 and 3 to be divisible with 6! Have a great day (or night)!
VikaD [51]3 years ago
3 0
To determine if a number is a multiple of 6, you can divide that number by 6. If the answer is a whole number, then the given number is a multiple of 6.

First, let's check 424. When you divide 424 by 6, you get 70.67 which is not a whole number, so 424 is not a multiple of 6. When you divide 106 by 6, you get 17.67 which is not a whole number so 106 isn't a multiple of 6. When you divide 333 by 6, you get 55.5 which isn't a whole number so 333 isn't a multiple of 6. Lastly, if you divide 882 by 6, you get 147 which is a whole number, so 882 is a multiple of 6. Therefore, D (882) is the answer.

I hope this helps.
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2 years ago
Show all work to factor x^4 − 17x^2 + 16 completely.
Dmitrij [34]

Answer:

x^{4}-17x^{2} +16 = (x -1)(x + 1)(x - 4)(x + 4)

Step-by-step explanation:

At first, let us find the first two factors of x^{4}-17x^{2} +16

∵ The sign of the last term is positive

∴ The middle signs of the two factors are the same

∵ The sign of the middle term is negative

∴ The middle signs of the two factors are negative

∵ x^{4} = x² × x² ⇒ first terms of the two factors

∵ 16 = -1 × -16 ⇒ second terms of the two factors

∵ x²(-1) + x²(-16) = -x² + -16x² = -17x² ⇒ the value of the middle term

∴ (x² - 1) and (x² - 16) are the factors of x^{4}-17x^{2} +16

Now let us factorize each factor

→ The factors of the binomial a² - b² (difference of two squares) are

   (a - b) and (a + b)

∵ x² - 1 is the difference of two squares

∴ Its factors are (x - 1) and (x + 1)

∵ x² - 16 is the difference of two squares

∴ Its factors are (x - 4) and (x + 4)

∵ (x -1), (x + 1), (x - 4), and (x + 4) are the factors of (x² - 1) and (x² - 16)

∵ (x² - 1) and (x² - 16) are the factors of x^{4}-17x^{2} +16

∴ (x -1), (x + 1), (x - 4), and (x + 4) are the factors of x^{4}-17x^{2} +16

∴  x^{4}-17x^{2} +16 = (x -1)(x + 1)(x - 4)(x + 4)

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