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Delicious77 [7]
3 years ago
5

There are 4 different math courses, 5 different science courses, and 2 different history courses. If a student must take one of

each, how many different ways can this be done?
Mathematics
1 answer:
rusak2 [61]3 years ago
6 0

A student can take three subjects in 40 ways.

<u>SOLUTION:</u>

Given that, there are 4 different math courses, 5 different science courses, and 2 different history courses.

A student must take one of each, how many different ways can this be done?

Now, number ways to take math course = 4

Number of ways to take science course = 5  

Number of ways to take history course = 2

So, now, total possible ways = product of possible ways for each course = 4 x 5 x 2 = 40 ways.

Hence, a student can take three subjects in 40 ways.

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4. Evaluate 6x-2y when x= 16 and y=7.<br> (1 Point)<br> 336<br> 110<br> 13<br> 82
Gnom [1K]

Answer:

82

Step-by-step explanation:

Given

6x - 2y ← substitute x = 16 and y = 7 into the expression

= 6(16) - 2(7)

= 96 - 14

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5 0
4 years ago
Using the quadratic formula to solve x2 = 5 – x, what are the values of x?
Ivenika [448]

Answer:

x²=5-x

x²+x-5=0

1x²+1x²-5=0

[ax²+bx²+c=0]

∆=b²-4ac

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meaning:

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4 0
2 years ago
please do this asap, i am in a really quick need, just type the answer, process is not required, i got -27, and i am pretty sure
pogonyaev

Answer:

The answer is 3

Step-by-step explanation:

8 0
3 years ago
Help me please I'm stuck!
alisha [4.7K]
My teachers taught me a trick make a C from the top to bottom

so 5  1/2 would be 

5 times 1 + 2 so denominator stays the same so it 7/2.



bottom one is 22/4

 make a C from top to bottom and multiply outer number to top add the bottom to that then keep denominator the same. 


Hope i helped. 
3 0
3 years ago
I cant figure out if its + or ×​
uranmaximum [27]

Answer:

+

Step-by-step explanation:

7 0
3 years ago
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