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lord [1]
2 years ago
5

Solve for x answer must be simplified -30< x/-4

Mathematics
2 answers:
Valentin [98]2 years ago
6 0

Answer:

x<120

Step-by-step explanation:

The X-120 Fury is the ultimate human air superiority aircraft. It is capable of single-handedly destroying any detected UFO. However it will not leave behind any wreckage to recover, and the Fury is extremely expensive to obtain, severely limiting its usage.

Brums [2.3K]2 years ago
5 0

Answer:

x < 120

Step-by-step explanation:

Step 1: Multiply both sides by -4.

  • -30 * -4 < \frac{x}{-4} * -4
  • 120 > x
  • x < 120

Therefore, x < 120.

Have a lovely rest of your day/night, and good luck with your assignments! ♡

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Solve: |2x + 3| -1 &lt; 4
dybincka [34]
|2x+3|-1<4
|2x+3|<5

1) when 2x +3 is positive     
2x+3<5
2x<2
x<1    (-∞, 1)

2) when 2x+3 is negative
-(2x+3)<5
-2x-3<5
-2x<8
x>-4  (-4, ∞)

(-∞, 1)∩(-4, ∞)=(-4,1)



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Answer:

Imagine how hard it was to create it all.

Step-by-step explanation:

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7 0
2 years ago
What is 64×34+8-3? Solve.
borishaifa [10]
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6 0
3 years ago
Someeee one?????????????????
Ad libitum [116K]

Answer:

Option B) a_{n} = 2\cdot 4^{n-1}

Step-by-step explanation:

The given geometric sequence is

2, 8, 32, 128,....

The general form of a geometric sequence is given by

a_{n} = a_{1}\cdot r^{n-1}

Where n is the nth term that we want to find out.

a₁ is the first term in the geometric sequence that is 2

r is the common ratio and can found by simply dividing any two consecutive numbers in the sequence,

r=\frac{8}{2} = 4

You can try other consecutive numbers too, you will get the same common ratio

r=\frac{32}{8} = 4

r=\frac{128}{32} = 4

So the common ratio is 4 in this case.

Substitute the value of a₁ and r into the above general equation

a_{n} = 2\cdot 4^{n-1}

This is the general form of the given geometric sequence.

Therefore, the correct option is B

Note: Don't multiply the first term and common ratio otherwise you wont get correct results.

Verification:

a_{n} = 2\cdot 4^{n-1}

Lets find out the 2nd term

Substitute n = 2

a_{2} = 2\cdot 4^{2-1} = 2\cdot 4^{1} = 2\cdot 4 = 8

Lets find out the 3rd term

Substitute n = 3

a_{3} = 2\cdot 4^{3-1} = 2\cdot 4^{2} = 2\cdot 16 = 32

Lets find out the 4th term

Substitute n = 4

a_{4} = 2\cdot 4^{4-1} = 2\cdot 4^{3} = 2\cdot 64 = 128

Lets find out the 5th term

Substitute n = 5

a_{5} = 2\cdot 4^{5-1} = 2\cdot 4^{4} = 2\cdot 256 = 512

Hence, we are getting correct results!

6 0
3 years ago
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