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xenn [34]
3 years ago
12

Shane returned from a trip to Las Vegas with $420 , which was75% more money than he had at the beginning of the trip. How much m

oney did Shane have at the beginning of his trip?
Mathematics
1 answer:
ioda3 years ago
3 0

Answer:

Shane had $240 at the beginning of his trip.

Step-by-step explanation:

Shane returned from a trip to Las Vegas with $420 and this is 75% more of at the beginning.

Let us assume the money he carried at the beginning of the trip was $x

At present he is having 75% more means total money he has = x+75% of x

This total amount is equal to $420

Therefore x + .75x = 420

x(1 +.75) =420

1.75 x = 420

Now by dividing both sides by 1.75

x = 420÷1.75

   = $240

Therefore the amount he carried in the beginning of the trip is $240.

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At the time of launch height of the object was 60 meters.

Step-by-step explanation:

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4 0
3 years ago
Tim has an after-school delivery service that he provides for several small retailers in town. He uses his bicycle and charges $
nlexa [21]

Answer:

<em>$4.84</em>

<em></em>

Step-by-step explanation:

Given that

For delivery within 1\frac{1}2 mi, charges = $1.25

For delivery within 1\frac{1}2 mi - 1\frac{3}4 mi, charges = $1.70

For delivery within 1\frac{3}4 mi - 2 mi, charges = $2.15

and

so on.

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For delivery within 2 mi - 2\frac{1}4 mi, charges = $2.60

For delivery within 2\frac{1}4 mi - 2\frac{1}2 mi, charges = $3.05

For delivery within 2\frac{1}2 mi - 2\frac{3}4 mi, charges = $3.50

For delivery within 2\frac{3}4 mi - 3 mi, charges = $3.95

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So, every 0.25 mi or \frac{1}4 mi increase in distance, there is an increase of $0.45 in the charges.

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So actual charges after increase of 10%

\Rightarrow \$4.40 \times \dfrac{110}{100}\\\Rightarrow \$4.40 \times 1.10\\\Rightarrow \bold{\$4.84}

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