The perimeter of a semicircle consists of two parts. (the curve and bottom)
That curve is half the distance around the circle, since it's been split in half.
The distance around a circle, the circumfrence, is equal to 2πr, where r is the radius of that circle. In this case, the circumfrence of the entire circle would be 16π. and so that curve would have a length of just 8π.
Using 3.14 for π, 8π = 8×3.14 = 25.12.
As for the flat part, that is the diameter (distance across) our circle.
The radius is the distance from the center of a circle to its edge, and always has half the length of the diameter. (you can break the diameter down into two radii)
If our radius is 8 meters, our diameter (the flat part of that semicircle) must be 16.
Now we add up the two parts of the perimeter...25.12 + 16 = 41.12.
Step-by-step explanation:
OCB=CBO(base angle of isosceles triangle are equal)
now,
OCB+CBO+BOC=180°(sum of angles of triangles)
BOC=180-62
BOC=118°
again,
x=BOC/2{inscribed angle is half of central angle standing on Same base}
x=118/2
x=59°
<h2>stay safe healthy and happy...</h2>
Answer:
<h2>
x = 15</h2>
Step-by-step explanation:
RQ < PR < PQ
TV < UV < UT
ΔPQR~ΔUTV ⇒ 
No
X would have to equal 6 or greater as if x was 5
5+3 is the same as 8
Answer:
The figure will result is cone ⇒ B
Step-by-step explanation:
<em>When a </em><em>right triangle is rotated about its vertical leg 360°</em><em>, then it formed </em><em>a cone</em><em> its radius is the horizontal leg of the triangle and its height is the vertical lege of the triangle</em>
<em />
In the given figure
∵ Triangle TRE is a right triangle
∴ The horizontal leg is RE
∴ The vertical leg is TR
∵ The triangle is rotated around the horizontal leg RE 360°
∴ It formed a cone its radius = TR and its height = RE
∴ The figure will result is the cone
