One way would be to find the distance from the point to the center of the circle and compare it to the radius
for

the center is (h,k) and the radius is r
and the distance formula is
distance between

and

is

r=radius
D=distance form (8,4) to center
if r>D, then (8,4) is inside the circle
if r=D, then (8,4) is on the circle
if r<D, then (8,4) is outside the circle
so



the radius is

center is (-2,3)
find distance between (8,4) and (-2,3)






≈4.2

≈10.04
do r<D
(8,4) is outside the circle
Answer:
1,350
Step-by-step explanation:
45*30=1,350
I think the trick is to add the two middle terms together. (And the 2 end terms).
8 - 12x
The variable is x. The coefficient is - 12.
8 is a constant.
The coefficient always goes with a variable.
3x^2 + 2x + 5
Nothing can be combined. The leading coefficient is 3 (which goes with the greatest power of the variable x^2 in this case) and the other coefficient is 2. 5 is a constant.