The amount of money that Davis has in this scenario is; $50
<h3>How to solve algebra word problems?</h3>
Let the amount of money he has be $X.
Now, if he buys 10 notebooks, he will have $10 left. Thus;
X - 10n = 10 -----(1)
If he buys 15 notebooks, he will be $10 short. Thus;
X - 15n = -10 ------(2)
Subtract eq 1 from eq 2 to get;
-5n = -20
n = -20/-5
n = 4
Thus;
X - 10(4) = 10
X = 10 + 40
n = $50
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It would be <0X <0Y Because they would need to math I am just guessing
It would be 12 dollars in US money
Answer:
X = 2
Step-by-step explanation:
4-14=5x
10=5x
10/5=5x/5
2=x
Answer:
None of those answers are correct
Step-by-step explanation:
There are no real solutions
Let's solve your equation step-by-step.
2+2x−3
2x+3
=
3x+4
x+2
Step 1: Cross-multiply.
2+2x−3
2x+3
=
3x+4
x+2
(2+2x−3)*(x+2)=(3x+4)*(2x+3)
2x2+3x−2=6x2+17x+12
Step 2: Subtract 6x^2+17x+12 from both sides.
2x2+3x−2−(6x2+17x+12)=6x2+17x+12−(6x2+17x+12)
−4x2−14x−14=0
For this equation: a=-4, b=-14, c=-14
−4x2+−14x+−14=0
Step 3: Use quadratic formula with a=-4, b=-14, c=-14.
x=
−b±√b2−4ac
2a
x=
−(−14)±√(−14)2−4(−4)(−14)
2(−4)
x=
14±√−28
−8
Answer:
No real solutions.