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4 years ago

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Rob is setting up a model train track that is 3 and 3 over 8feet long. No telephone pole is needed at the start of the track. Ho

wever, along the track, he places a telephone pole every 3 over 8foot apart. How many telephone poles does he need? (Input number values only)

1 answer:

Mila [183]4 years ago

3 0

So, $\frac{3*3}{8} 
$ is 9/8 so its 3 poles

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The points -4. -4 -4, 4

Ilia_Sergeevich [38]

Answer:

whats the question?

Step-by-step explanation:

I don't get the question so what is the question?

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3 years ago

Could someone answer these 3 for me?

KengaRu [80]

Answer:

x=4.77

Angle 3=98.32 degrees

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Step-by-step explanation:

(Assuming these are parallel lines), Angle 3 and angle 5 are equal because they are alternate Angles. Therefore we can write the following equation to solves for x:

16x+22=3x+84 (angle 3=angle5)

Which we can now solve:

16x +22 - 22 - 3x=3x-3x+84-22

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x=4.77 (2dp)

We can then use this x to calculate angle 3:

16(4.77)+22

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Finally,

Angle 6 and angle 3 are interior angles, so they add up to 180 degrees.

So to find angle 6,we can just subtract angle 3 from 180:

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3 years ago

Need help on this Math problem

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3 years ago

reply to this with answer Which best proves why the expressions 4 (x + 3) + 2 x and 6 (x + 2) must be equivalent expressions?

Ivan

Answer:

Given expressions are equivalent.

Step-by-step explanation:

Given expression:

4 (x + 3) + 2x and 6 (x + 2)

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3 years ago

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Alex_Xolod [135]

Answer:

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The third one.

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$h(-6) = \sqrt[3]{-(-6)+2}= \sqrt[3]{6+2}= \sqrt[3]{8} = 2\\h(1) = \sqrt[3]{-1+2}= \sqrt[3]{1}= 1\\h(2) = \sqrt[3]{-2+2}= \sqrt[3]{0}= 0\\h(3) = \sqrt[3]{-3+2}= \sqrt[3]{1}= 1\\h(10) = \sqrt[3]{-10+2}= \sqrt[3]{-8}= -2$

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3 years ago

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