So 7×6=42 and 7×4=28 GCF is 7 so 7x(6x+4)
Option A
The restaurant Manager can afford at most 10 employees for the day
<em><u>Solution:</u></em>
Given that restaurant manager can spend at most $600 a day for operating costs and payroll
It costs $100 each day to operate the bank and $50 dollars a day for each employee
The given inequality is:

Where , "x" is the number of employees per day
Let us solve the inequality for "x"

Add -100 on both sides of inequality

Divide by 50 on both sides of inequality

Hence the restaurant Manager can afford at most 10 employees for the day
Thus option A is correct
Sweater = 400
coats = 100
difference= 300
in an equation it would be
4x-x=300
so
3x=300
x=100
sweaters= 4x= 400
coats= x= 100
Answer:
Selling price=rs.600.
Profit of rs=100.
Step-by-step explanation:
C.P=500; profit%=20%
S.P.=100+profit%×C.P/100
S.P=120×500/100
=rs.600
S.P>C.P
Profit S.P-C.P
600-500=100
he gained for rs.100.