First of all, 2^n and 3^n are exponentials with different bases, and thus their sum cannot be simplified beyond 2^n + 3^n. In other words, these two functions cannot be combined ino one function (such as 4^n).
You may gain much more insight by graphing 2^n, 3^n and 4^n to determine whether there is truth in the given statement or not.
Answer:
7.5 years.
Step-by-step explanation:
Use A = 1400(1+0.02)^7.5
The 1400 is the starting money. The 1 is a constant. The 0.02 is the 2% in decimal form. And the 7.5 is years. I found that by just continually increasing it until it hit 1624.
Hope this helps
H(x) = -5x - 10
h(-2) = -5(-2) - 10
h(-2) = 10 - 10
h(-2) = 0
The solution is 0.
<span>half-life means you divide by 2
21.6 / 3.6 = 6 hf (hf = half-life)
then you divide by 2^6
6.02 x 10^23 / 2^6 = 9.40625 x 10^21 atoms
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3hf ===> 2^3
10.0 / 2^3 = 1.25 gram (remaining)
answer : 10 - 1.25 = 8.75g
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128 / 2^n = 2
64 = 2^n
n = 6
24 /6 = 4
4 days is the half-live of the sample
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2.5/4.46 of 50% initial mass
(2.5/4.46) x 0.5 x 2 = 0.5605 g
answer: 2 - 0.5605 = 1.4395 g
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2^7 = 128
so 7 half-lifes
7* 8040 = 56200 days
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the time of 10 half-lifes
= 10 x 0.334s = 3.34s </span><span>
</span>
Answer:
thanks your amazing
Step-by-step explanation:
