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3 years ago

HELP ME PLEASE PLEASE IM BEGGING

Mathematics

1 answer:

Llana [10]3 years ago

5 0

Answer:

Consistent and independent

Step-by-step explanation:

This is bcoz dependent lines overlap each other, where as inconsistent lines dont intersect

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igor_vitrenko [27]

Answer:

umef leaf ninja the frog held a

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3 years ago

15 pounds of ham to make 35 sandwiches. How much ham per sandwich?

polet [3.4K]

15 pounds / 35 sandwiches ~ 0.43 pounds ham per sandwich

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2 years ago

PLZ HURRY!!!! 15 POINTS!

Daniel [21]

I think it’s 7.5 minutes

5 0

3 years ago

Read 2 more answers

Find the surface area.

denpristay [2]

Step-by-step explanation:

a rectangular prism (like this brick) has the same basic structure as a cube (like a die) : it has 6 sides.

while a die has 6 equal sides, a rectangular prism has 3 pairs of equal sides :

top and bottom

left and right

front and back

all we have to do is calculate the areas of the 6 rectangles and add them up. that's it.

your remember, the area of a rectangle is

length × width

in our case we have

top and bottom : 2.5×11.5 × 2 = 28.75×2 = 57.5 in²

left and right : 2.5×5 × 2 = 12.5×2 = 25 in²

front and back : 11.5×5 × 2 = 57.5×2 = 115 in²

so, the total surface area of the whole block is

57.5 + 25 + 115 = 197.5 in²

5 0

1 year ago

A 500-gallon tank initially contains 220 gallons of pure distilled water. Brine containing 5 pounds of salt per gallon flows int

Wittaler [7]

Answer: The amount of salt in the tank after 8 minutes is 36.52 pounds.

Step-by-step explanation:

Salt in the tank is modelled by the Principle of Mass Conservation, which states:

(Salt mass rate per unit time to the tank) - (Salt mass per unit time from the tank) = (Salt accumulation rate of the tank)

Flow is measured as the product of salt concentration and flow. A well stirred mixture means that salt concentrations within tank and in the output mass flow are the same. Inflow salt concentration remains constant. Hence:

$c_{0} \cdot f_{in} - c(t) \cdot f_{out} = \frac{d(V_{tank}(t) \cdot c(t))}{dt}$

By expanding the previous equation:

$c_{0} \cdot f_{in} - c(t) \cdot f_{out} = V_{tank}(t) \cdot \frac{dc(t)}{dt} + \frac{dV_{tank}(t)}{dt} \cdot c(t)$

The tank capacity and capacity rate of change given in gallons and gallons per minute are, respectivelly:

$V_{tank} = 220\\\frac{dV_{tank}(t)}{dt} = 0$

Since there is no accumulation within the tank, expression is simplified to this:

$c_{0} \cdot f_{in} - c(t) \cdot f_{out} = V_{tank}(t) \cdot \frac{dc(t)}{dt}$

By rearranging the expression, it is noticed the presence of a First-Order Non-Homogeneous Linear Ordinary Differential Equation:

$V_{tank} \cdot \frac{dc(t)}{dt} + f_{out} \cdot c(t) = c_0 \cdot f_{in}$ , where $c(0) = 0 \frac{pounds}{gallon}$ .

$\frac{dc(t)}{dt} + \frac{f_{out}}{V_{tank}} \cdot c(t) = \frac{c_0}{V_{tank}} \cdot f_{in}$

The solution of this equation is:

$c(t) = \frac{c_{0}}{f_{out}} \cdot ({1-e^{-\frac{f_{out}}{V_{tank}}\cdot t }})$

The salt concentration after 8 minutes is:

$c(8) = 0.166 \frac{pounds}{gallon}$

The instantaneous amount of salt in the tank is:

$m_{salt} = (0.166 \frac{pounds}{gallon}) \cdot (220 gallons)\\m_{salt} = 36.52 pounds$

3 0

3 years ago