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3 years ago

Question12....................................

Mathematics

1 answer:

tatyana61 [14]3 years ago

5 0

Answer:

u = ± 4

Step-by-step explanation:

Given

u² = 16 ( take the square root of both sides )

u = ± $\sqrt{16}$ = ± 4

u = - 4, u = 4

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Drag the tiles to the boxes to form correct pairs.<br> Match the pairs of equivalent expressions.

Masja [62]

Answer:

Step-by-step explanation:

look this solution

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3 years ago

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I need help with these three problems please

Liono4ka [1.6K]

Answer:

Q7. 11.3 inches (3 s.f.)

Q8. 96.2 ft

Q9. 36.4cm

Step-by-step explanation:

Q7. Please see attached picture for full solution.

Q8. Let the length of a side of the square be x ft.

Applying Pythagoras' Theorem,

$34^{2} = {x}^{2} + {x}^{2} \\ 2 {x}^{2} = 1156 \\ {x}^{2} = 1156 \div 2 \\ {x}^{2} = 578 \\ x = \sqrt{578} \\$

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Q9. Equilateral triangles have 3 equal sides and each interior angle is 60°.

Since the perimeter of the equilateral triangle is 126cm,

length of each side= 126÷3 = 42 cm

The green line drawn in picture 3 is the altitude of the triangle.

Let the altitude of the triangle be x cm.

sin 60°= $\frac{x}{42}$

$\frac{ \sqrt{3} }{2} = \frac{x}{42} \\ x = \frac{ \sqrt{3} }{2} \times 42 \\ x = 21 \sqrt{3} \\ x = 36.4$

(to 3 s.f.)

Therefore, the length of the altitude of the triangle is 36.4cm.

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3 years ago

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Plz help I will give you BRAINLIESt 5stars

Svetradugi [14.3K]

Answer:

I will just give you the way of solving it

Step-by-step explanation:

First you have to change the sgape of the equation and it will become like this :

-6y=-2x+12

And then:

Y=0.33x+2

And then you have to give values to x and find y

For example i will make x zero (0)

It will become

Y=0.33(0)+12

=+12

And the points are (0,+12)

Go on like this and draw the line

Good luck

Sorry for bad english

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3 years ago

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KATRIN_1 [288]

1 1/4 cups of flour was used

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3 years ago

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Solve number problem 8

butalik [34]

Two consecutive odd integers have a difference of 2. If you let the smaller one of them be x, the other one is x + 2.

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