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algol [13]
2 years ago
6

Use the quadratic formula s to solve 2y^2-6y-8=0

Mathematics
1 answer:
Korvikt [17]2 years ago
6 0

Answer:

{4, - 1}

Step-by-step explanation:

Given

2y² - 6y - 8 = 0 ← in standard form

with a = 2, b = - 6, c = - 8

Using the quadratic formula to solve for y

y = ( - (- 6) ± \sqrt{(-6)^2-(4(2)(-8)} ) / (2 × 2)

  = ( 6 ± \sqrt{36+64} ) / 4

  = ( 6 ± \sqrt{100} ) / 4

  = ( 6 ± 10 ) / 4

x = \frac{6+10}{4} = \frac{16}{4} = 4

OR

x = \frac{6-10}{4} = \frac{-4}{4} = - 1

Solution is { 4, - 1 }

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Step-by-step explanation:

3 0
3 years ago
Cos 0 = 12/15. find sin 0.
valentina_108 [34]

Answer:

sin \theta = \frac{3}{5}

Step-by-step explanation:

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       = 1 - (\frac{12}{15})^2\\\\= 1 - \frac{144}{225}\\\\= \frac{225 - 144}{225}\\\\=\frac{81}{225}

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3 0
3 years ago
Given the graph below, what is the zero(s)?
JulsSmile [24]

Answer:

Great job!

Step-by-step explanation:

6 0
3 years ago
Help me please math
Dominik [7]

13+9=22

5+18=23

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½x9x18=81

506-32.5-45-81=347.5

5 0
2 years ago
Pls help this is due very soon
Viefleur [7K]
10x16 = 160 cm

160x 3.14 = 502.4 cm

502.4 ≈ 500 cm

7 0
3 years ago
Read 2 more answers
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