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algol [13]
3 years ago
6

Use the quadratic formula s to solve 2y^2-6y-8=0

Mathematics
1 answer:
Korvikt [17]3 years ago
6 0

Answer:

{4, - 1}

Step-by-step explanation:

Given

2y² - 6y - 8 = 0 ← in standard form

with a = 2, b = - 6, c = - 8

Using the quadratic formula to solve for y

y = ( - (- 6) ± \sqrt{(-6)^2-(4(2)(-8)} ) / (2 × 2)

  = ( 6 ± \sqrt{36+64} ) / 4

  = ( 6 ± \sqrt{100} ) / 4

  = ( 6 ± 10 ) / 4

x = \frac{6+10}{4} = \frac{16}{4} = 4

OR

x = \frac{6-10}{4} = \frac{-4}{4} = - 1

Solution is { 4, - 1 }

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