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Drupady [299]
3 years ago
7

Please help me!!!!! Im confused help with these 3 and tell me how u got it

Mathematics
1 answer:
AnnZ [28]3 years ago
6 0
Hi

45. A) x

46. B) 18

47. D) 1/27
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Express a ratio in the form of 1:n<br> 5:45
Radda [10]

Answer:

1:9

Step-by-step explanation:

you divide both sides by the right number

for example the right number in this one is 5 so u divide 5 by it self and 5 by 45 to get your answer

6 0
2 years ago
Solve the equation -6 = -9 - 3x for x
Xelga [282]

Answer:

-6= - 9 - 3x

3x = -9 + 6

3x = - 3

Therefore x = -1

3 0
3 years ago
A recipe needs 4/5 cups of butter for every 2 cups of flour. If you plan to use 3 cups of flour, how much butter will you need?
DedPeter [7]

Answer:

1 1/5 cups of butter

Step-by-step explanation:

4/5=2

      =3

 4/5 x 3=12/5

12/5 / 2

12/5 x 1/2=1 1/5

7 0
3 years ago
Read 2 more answers
An engineer designed a valve that will regulate water pressure on an automobile engine. The engineer designed the valve such tha
natita [175]

Answer:

Step-by-step explanation:

Given that:

Population Mean = 7.1

sample size = 24

Sample mean = 7.3

Standard deviation = 1.0

Level of significance = 0.025

The null hypothesis:

H_o: \mu = 7.1

The alternative hypothesis:

H_a: \mu > 7.1

This test is right-tailed.

degree \ of \  freedom=  n - 1 \\ \\ degree \  of \  freedom  =  24 - 1 \\ \\ degree \ of \  freedom   = 23

Rejection region: at ∝ = 0.025 and df of 23, the critical value of the right-tailed test t_c = 2.069

The test statistics can be computed as:

t = \dfrac{ \hat X - \mu_o}{\dfrac{s}{\sqrt{n}}}

t = \dfrac{ 7.3-7.1}{\dfrac{1}{\sqrt{24}}}

t = \dfrac{0.2}{0.204}

t = 0.980

Decision rule:

Since the calculated value of t is lesser than, i.e t = 0.980 < t_c = 2.069, then we do not reject the null hypothesis.

Conclusion:

We conclude that there is insufficient evidence to claim that the population mean is greater than 7.1 at 0.025 level of significance.

6 0
3 years ago
Write the series using summation notation. Then find the sum of the series.
ivolga24 [154]

Hello, please consider the following.

\displaystyle 1+2+3+...+12=\sum_{k=1}^{k=12} {k}=\dfrac{12*13}{2}=6*13=78

For the second we will need to put on the same denominator.

\displaystyle \dfrac{1}{2}+\dfrac{1}{4}+...+\dfrac{1}{14}=\sum_{k=1}^{k=7} {\dfrac{1}{2k}}\\\\=\dfrac{1}{2}\dfrac{420+210+140+105+84+70+60}{5*7*3*2*2}\\\\=\dfrac{1}{2}\dfrac{1089}{420}\\\\=\dfrac{1089}{840}=1.296429...

Thank you.

3 0
3 years ago
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