Honestly, I'm trying my best to solve this but my Math XL is being so rude.
2 answers:
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The pool can hold 65.84 ft³ of water
<u>Explanation:</u>
Given:
Shape of pool = octagonal
Base area of the pool = 22 ft²
Depth of the pool = 3 feet
Volume, V = ?
We know:
Area of octagon = 2 ( 1 + √2) a²
22 ft² = 2 ( 1 + √2 ) a²
a² =
a² = 4.55
a = 2.132 ft
Side length of the octagon is 2.132 ft
We know:
Volume of octagon =
Therefore, the pool can hold 65.84 ft³ of water
Answer:
BC=√7
Step-by-step explanation:
AC=4
AC=AH+HC
=3HC+HC
=4HC
HC=1/4AC=1/4×4=1
AH=3HC=3×1=3
BH⊥ AC
AB=AC=4