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Novosadov [1.4K]
2 years ago
10

Honestly, I'm trying my best to solve this but my Math XL is being so rude. ​

Mathematics
2 answers:
kogti [31]2 years ago
7 0
19 is the correct answer
Valentin [98]2 years ago
5 0
<h3>Answer:  19</h3>

==============================================================

Explanation:

T is the midpoint of PQ, which means T splits PQ into two equal parts. Those parts being PT and TQ.

Set them equal to each other and solve for x.

PT = TQ

3x+7 = 7x-9

3x-7x = -9-7

-4x = -16

x = -16/(-4)

x = 4

So,

PT = 3x+7 = 3*4+7 = 19

TQ = 7x-9 = 7*4-9 = 19

Both PT and TQ are 19 units long to help confirm the answer.

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Look at the graph below. Which of the following best represents the slope of the line? A. -3 B. - 1 3 C. 1 3 D. 3
Salsk061 [2.6K]

Answer and Explanation:

The line seems to pass trough the points (0,6) and (-3,4).

Slope is: m=\frac{y_2-y_1}{x_2-x_1}

m=\frac{4-6}{-3-0} =\frac{-2}{-3} =\boxed{\frac{2}{3}}

The slope of the line should be \frac{2}{3}.

3 0
3 years ago
PLEASE HELP! GIVEE ME THE 14 ANSWERS FOR THIS FOR BRAINLIEST
gulaghasi [49]

Answer:

Step-by-step explanation:

oh boy

1) 9 < 16

2) -4 < 5

3) 18 > -19

4) -38 < -16

5) 6 > 4

6) -14 > -25

7) -45 > -55

8) -2 > -10

9) -4, -1, 1, 3, 6

10) -15, -13, -5, 8

11) -9, -6, -5, -1, 0

12) -4, -2, 1, 3

13) -10, -9, 7, 8, 11

14) -33, -25, -14, -4, 7

hope this helps <3

6 0
3 years ago
A particle whose mass is 4 kg moves in xyplane with a constant speed of 2 m/s in the positive x-direction along y = 6 m. Find th
s2008m [1.1K]

Answer: 32.8kgm^2/s

Step-by-step explanation:

1. Angular momentum is a product of linear momentum and the distance of the object from a rotation axis.

2. Linear momentum (L) is given as :

L = mv

Where: m= mass = 4kg

v= velocity= 2m/s

=> L = 8kgm/s

Angular momentum (A) = L x centre distance (d) of object from a rotation axis

d = √(0.9-0)^2 + (10-6)^2 = 4.1m

=> A = 8 x 4.1 = 32.8kgm^2/s.

5 0
3 years ago
What is the factored form of 2x2 + x-3?
Vesnalui [34]

Answer:

Step-by-step explanation:

a = 2, b = 1, c = -3

We need to factor this by finding the product of a and c, then from there find which factors of a * c will either add or subtract to give us b.

a * c = 6  and the factors of 6 and 1 and 6, 2 and 3.  Well, 6 - 1 doesn't equal 1 and neither does 6 + 1.  So our factors are 3 and 2.  In order to combine those to get a 1 (our b), we will subtract 2 from 3 since 3 - 2 = 1.  That means that 3 is positive and 2 is negative.  Filling in the formula with 3 and 2 in place of 1 looks like this (always remember to put the absolute value of the largest number first):

2x^2+3x-2x-3=0

Group the first 2 terms together and the second 2 term together in order to factor:

(2x^2+3x)-(2x-3)=0 and factor out what's common in each set of parenthesis.

x(2x+3)-1(2x+3)=0

Notice that when we factor out a -1 from the second set of parenthesis, we can distribute it back in to get the equation we started with.  We know that factoring by grouping "works" if what is inside both sets of parenthesis is exactly the same.  Ours are identical: (2x + 3).  That is common now, and can be factored out:

(2x+3)(x-1)=0

That matches your first choice

6 0
3 years ago
K - 2( k - ( 2- k ))-2
Naily [24]
K-2 I think I'm not sure though
4 0
3 years ago
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