Ask question

Ask question

All categories

Irina-Kira [14]

3 years ago

8

A mathematics journal has accepted 15 articles for publication. However, due to budgetary restraints only 9 articles can be publ

ished this month. How many ways can the journal editor assemble 9 of the 15 articles for publication?

1 answer:

Katena32 [7]3 years ago

4 0

15!/(15-9)!= 32432400

i hate these so much hope it helps! :)

You might be interested in

Are lines JN and KM parallel?

Ahat [919]

Answer:yes

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

Which of the following expressions is equal to -3X2-27?

ale4655 [162]

Answer: B

Step-by-step explanation:

-3x^2-9xi+9ix-27

-3x^2-27

8 0

3 years ago

How do you write 6,007,200 in words

kirill [66]

Six million, seven thousand two hundred

3 0

3 years ago

Read 2 more answers

Which number is irrational?

lisov135 [29]

Answer:

C.

Step-by-step explanation:

The answer C is not rational

6 0

3 years ago

Read 2 more answers

The indefinite integral can be found in more than one way. First use the substitution method to find the indefinite integral. Th

Fantom [35]

Answer:

∫ $6x^5(x^6-2)\,dx$ = $\frac{1}{2}(x^6-2)^2+C$

Step-by-step explanation:

To find:

∫ $6x^5(x^6-2)\,dx$

Solution:

Method of substitution:

Let $x^6-2=t$

Differentiate both sides with respect to $t$

$6x^5\,dx=dt$

[use $(x^n)'=nx^{n-1}$ ]

So,

∫ $6x^5(x^6-2)\,dx$ = ∫ $t\,dt$ = $\frac{t^2}{2}+C_1$ where $C_1$ is a variable.

(Use ∫ $t^n\,dt=\frac{t^{n+1} }{n+1}$ )

Put $t=x^6-2$

∫ $6x^5(x^6-2)\,dx$ = $\frac{1}{2}(x^6-2)^2+C_1$

Use $(a-b)^2=a^2+b^2-2ab$

So,

∫ $6x^5(x^6-2)\,dx$ = $\frac{1}{2}(x^6-2)^2+C_1=\frac{1}{2}(x^{12}+4-4x^6)+C_1=\frac{x^{12} }{2}-2x^6+2+C_1=\frac{x^{12} }{2}-2x^6+C$

where $C=2+C_1$

Without using substitution:

∫ $6x^5(x^6-2)\,dx$ = ∫ $6x^{11}-12x^5\,dx$ = $\frac{6x^{12} }{12}-\frac{12x^6}{6}+C=\frac{x^{12} }{2}-2x^6+C$

So, same answer is obtained in both the cases.

7 0

2 years ago