The distance of the spaceship in discuss as in the task content given can be evaluated as; 800miles.
<h3>What is the distance the spaceship travels in 4 minutes?</h3>
The distance travelled by the spaceship in discuss can be evaluated by means of the slope of the linear relationship as follows;
Hence it follows from ratios that by observation, the linear relationship has a slope of 200mi/min.
Consequently, we can evaluate the distance travelled after 4 minutes as;
Distance = 200 × 4 = 800mi.
Ultimately, the distance travelled per minute by the spaceship is; 800mi.
Remarks:
600 miles
520 miles
800 miles
1,080 miles
Read more on ratios;
brainly.com/question/13513438
#SPJ1
Step-by-step explanation:
<u>Given</u><u>:</u>
Central Enlargement.
AC=4
AB=5
BC=3
Opp=3
Hyp=5
<u>Required</u><u>:</u>
Sin<A
<u>Formula</u><u>:</u>
Sin<A=Opp/hyp
<u>Solution</u><u>:</u>
Sin<A=Opp/Hyp
Sin<A=3/5 or 0.6
Would be x^2-5-6 so the 0s would be (x-6)(x+1) so 6 and -1
I think it’s D, sorry if I’m wrong.
Answer:
Step-by-step explanation:
7√x-9√x+10√2+√2 = √x ( 7 - 9) +√2 ( 10+1) = - 2√x + 11√2