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3 years ago

Which variable expression represents the phrase the product of h and p

Mathematics

1 answer:

lutik1710 [3]3 years ago

7 0

Answer:

Step-by-step explanation:

Here, we want to write the variable expression representing the product of h and p

Mathematically, what we just have to do here is multiply h by p

That will be;

h * p = hp

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The number of phone calls received by the complaint department of a

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5000hhhhhgbbbv hhgh cuh fghjdjdjdjjdd

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Henry has $21.50 to ride the trolley around San Francisco this week. It will cost him $0.50 every time he rides. Identify the de

myrzilka [38]

Answer:

Dependent: Cost of the ride.

Independent : Number of rides.

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The independent variable is the variable what we change and the dependent variable is the variables which changes because of that changes.

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Consider the system of differential equations dxdt=−4ydydt=−4x. Convert this system to a second order differential equation in y

koban [17]

$\dfrac{\mathrm dy}{\mathrm dt}=-4x\implies x=-\dfrac14\dfrac{\mathrm dy}{\mathrm dt}\implies\dfrac{\mathrm dx}{\mathrm dt}=-\dfrac14\dfrac{\mathrm d^2y}{\mathrm dt^2}$

Substituting this into the other ODE gives

$-\dfrac14\dfrac{\mathrm d^2y}{\mathrm dt^2}=-4y\implies y''-16y=0$

Since $x(t)=-\dfrac14y'(t)$ , it follows that $x(0)=-\dfrac14y'(0)=4\implies y'(0)=-16$ . The ODE in $y$ has characteristic equation

$r^2-16=0$

with roots $r=\pm4$ , admitting the characteristic solution

$y_c=C_1e^{4t}+C_2e^{-4t}$

From the initial conditions we get

$y(0)=5\implies 5=C_1+C_2$

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$\implies C_1=\dfrac12,C_2=\dfrac92$

So we have

$\boxed{y(t)=\dfrac12e^{4t}+\dfrac92e^{-4t}}$

Take the derivative and multiply it by -1/4 to get the solution for $x(t)$ :

$-\dfrac14y'(t)=\boxed{x(t)=-\dfrac12e^{4t}+\dfrac92e^{-4t}}$

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3 years ago

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brilliants [131]

Answer:

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Step-by-step explanation:

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