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3 years ago

1.9.2) If the programme started at 12:30 pm, at what time will it end?

Mathematics

1 answer:

DerKrebs [107]3 years ago

3 0

Answer:

We need to know what the program is...

Step-by-step explanation:

This question is literally unanswerable as some programs last 2 seconds and some would last thousands of years. More context as to what the program is please.

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The tank at a gas station contained 400 gallons of gas. A tanker truck that contained 8,100 gallons of gas filled the station's

spin [16.1K]

Answer:

1300

Step-by-step explanation:

Let the amount put in the station's tank = x

4(400 + x) = 8100 - x Remove the brackets

1600 + 4x = 8100 - x Subtract 1600 from both sides

1600 - 1600 + 4x = 8100 - 1600 - x Do the subtraction

4x = 6500 - x Add x to both sides

4x + x = 6500 - x + x

5x = 6500 Divide by 5

5x/5 = 6500/5

x = 1300

1300 gallons were added to the station's tank.

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3 years ago

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Which term best describes the expression 2x + 2dy−3?

Margarita [4]

Answer:

the term is separated by minus (-) and plus (+) .

therefore this term is trinomial.

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3 years ago

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1-58. Mr. Wright was making a table to figure out how much it costs to send a certain numt

Drupady [299]

A table of values can be used to represent variables that are directly proportional.

The complete table of proportions is:

$\left[\begin{array}{ccccccccc}Letters&10&2&[150 ]&7&1&500&[420] \\Cost&0.45&0.90&6.75&[0.315]&[0.045 ]&[22.5 ] & 18.90\end{array}\right]$

Given that

$\left[\begin{array}{ccccccccc}Letters&10&2&[\ ]&7&1&500&[\ ] \\Cost&0.45&0.90&6.75&[\ ]&[\ ]&[\ ] & 18.90\end{array}\right]$

Let:

$L \to$ Letters

$C \to$ Cost

Using proportional reasoning, we have:

$C = kL$

Where

$k \to$ ratio of proportion

For the first values of C and L, we have:

$C = kL$

$0.45 = k \times 10$

Divide both sides by 10

$k = 0.045$

So, the equation of proportion is:

$C = 0.045L$

When C = 6.75, we have:

$C = 0.045L$

$6.75 = 0.045L$

Solve for L

$L = \frac{6.75}{0.045}$

$L = 150$

When L = 7, we have:

$C = 0.045L$

$C = 0.045 \times 7$

$C = 0.315$

When L = 1, we have:

$C = 0.045L$

$C = 0.045 \times 1$

$C = 0.045$

When L = 500, we have:

$C =0.045L\\$

$C =0.045 \times 500$

$C =22.5$

When C = 18.90, we have:

$C = 0.045L$

$18.90 = 0.045L$

Solve for L

$L=\frac{18.90}{0.045}$

$L=420$

Hence, the complete table is:

$\left[\begin{array}{ccccccccc}Letters&10&2&[150 ]&7&1&500&[420] \\Cost&0.45&0.90&6.75&[0.315]&[0.045 ]&[22.5 ] & 18.90\end{array}\right]$

1.9.2) If the programme started at 12:30 pm, at what time will it end?​

1.9.2) If the programme started at 12:30 pm, at what time will it end?