3 years ago

PLEASE I NEED HELP!!!!

Mathematics

1 answer:

Zigmanuir [339]3 years ago

4 0

The potential problem may be that the race of people aren’t all Canadians

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In the following diagram HI || JK.<br><br>What is the measure of x?

otez555 [7]

Answer:

Step-by-step explanation:

60 + 56 + x = 180

116 + x = 180

x = 180 - 116

x = 64

7 0

3 years ago

Read 2 more answers

8+ negative one plus -3 as an integer

Zolol [24]

8+~1-3=4
Explanation-
8-1 is the same as 8+~1 so=7
7-3=4

5 0

3 years ago

Solve for m. √m-7 = n+3

Elden [556K]

Answer:

$m=n^{2} +20n +100$

Step-by-step explanation:

Solve for m

by simplifying both sides of the equation, then isolating the variable.

$m=n^{2} +20n +100$

<u>Hope this helps</u>

3 0

3 years ago

Make a Matlab script to make row 2 of matrix A equal to first row of A multiplied by the negative of the first element of row 2

stira [4]

Answer:

$X=\begin{Bmatrix}2& 1 &10 \\-3 & 5 & 4\end{Bmatrix}$

Step-by-step explanation:

From the question we are told that

Matrix is given as $A=\begin{Bmatrix}2 & -1 & 10\\-3 & 8 & 4\end{Bmatrix}$

Generally let the change in matrix be given as X

$X_1_2 = 2*(-(-1)) + - 1 = 1X_2_2 = -3 * (-(-1))+ 8 = 5$

Matlab output

$A=[2 -1 10;-3 8 4]\\a=(A(1,1)*-A(1,2))+A(1,2)\\b=(A(2,1)*-A(1,2))+A(2,2)\\X=[A(1,1) a A(1,3); A(2,1) b A(2,3)]\\$

Generally the matrix that makes row 2 of matrix A equal to first row of A multiplied by the negative of the first element of row 2 plus the original row is

$X=\begin{Bmatrix}2& 1 &10 \\-3 & 5 & 4\end{Bmatrix}$

6 0

3 years ago

Jim currently has $1,250 in his bank account and Sally has $1,400 in her bank account. Jim deposits $27.50 per week and Sally

ale4655 [162]

Answer:

20 weeks.

Step-by-step explanation:

The equations of money deposits of each bankholder as a function of time are, respectively:

Jim

$p_{1} = 1250 + 27.50\cdot t\\$

Sally

$p_{2} = 1400 +20\cdot t$

The number of weeks so that both have the same amount of money is:

$1250 + 27.50\cdot t = 1400 + 20\cdot t$

$7.50\cdot t = 150$

$t = 20$

8 0

3 years ago