Answer:
The correct answer is 29 grams.
Explanation:
Based on the given question, the reaction will be,
CH3CH=CHCH3 + H2 ⇒ CH3CH2CH2CH3
The molecular weight of butene is 56 grams per mole, and the molecular weight of butane is 58 grams per mole.
Thus, it can be said that 56 grams of butene reacts with hydrogen gas and produces 58 grams of butane.
Therefore, 28 grams of butene when reacts with hydrogen gas to give,
= 58/56 * 28 = 29 grams of butane.
Hence, the mass of butane produced will be 29 grams.
Hybridization of atomic orbitals produces orbital shapes and spatial orientations that correlate to those predicted in VSEPR theory.
<h3>What is VSEPR theory ?</h3>
The number of electron pairs surrounding an individual molecule's core atoms can be used to forecast a molecule's shape using the chemical model known as the valence shell electron pair repulsion hypothesis. The two principal creators of the theory, Ronald Gillespie and Ronald Nyholm, gave it the additional moniker Gillespie-Nyholm theory.
- Hybrid orbital theory explains how these forms are created, while VSEPR theory predicts the shapes of molecules. VSEPR theory's central tenet is that electron pairs—both those in bonds and those that are alone repel one another. "Groups" refers to the electron pairs, both in bonds and lone pairs.
Learn more about VSEPR theory here:
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There are four Hydrogen atoms in one molecule of Methane (CH₄).
And there are 6.022×10²³ molecules in 1 mole of CH₄.
So,
Number of Hydrogen atoms is 1 mole of CH₄ are,
= 6.022 × 10²³ × 4
= 2.4 ×10²⁴ Hydrogen Atoms
Now calculating for 2 moles,
As,
1 mole of CH₄ contains = 2.4 ×10²⁴ Hydrogen Atom
Then,
2 moles of CH₄ will contain = X Hydrogen Atoms
Solving for X,
X = (2 moles × 2.4 ×10²⁴ Hydrogen Atom) ÷ 1 mole
X = 4.8 × 10²⁴ Hydrogen Atoms
Answer:
The ideal gas law ... A gas turbine, which uses continuous combustion, simply exhausts its ... This makes them ideal for use in vehicles, as they also start up more ... A four stroke engine delivers one power stroke for every two cycles of ... ignition, exhaust) however, these steps occur 3 times per one spin of. Internal combustion engine.
Explanation:
Answer:
2HBr(g) → H₂ (g) + Br₂ (g)
2Al + Fe₂O₃ → 2Fe + Al₂O₃
2C₄H₆ + 11O₂ → 8CO₂ + 6H₂O
Ag + Pb₃(PO₄)₂ → No reaction
K₂CO₃ + Cal₂ → 2KI + CaCO₃
Explanation:
1st reaction:
2HBr(g) → H₂ (g) + Br₂ (g)
HBr produces hydrogen and bromine gas.
Second reaction:
2Al + Fe₂O₃ → 2Fe + Al₂O₃
Aluminium is more reactive than iron that's why it displace the iron from oxide and form aluminium oxide.
3rd reaction:
2C₄H₆ + 11O₂ → 8CO₂ + 6H₂O
Butyne burn in the presence of oxygen and produces carbondioxide and water.
4th reaction:
Ag + Pb₃(PO₄)₂ → No reaction
Because lead is more more reactive than silver that's why silver can not displace the lead to react with (PO₄)₂ .
5th reaction:
K₂CO₃ + Cal₂ → 2KI + CaCO₃
potassium carbonate react with calcium iodide and produces calcium carbonate and potassium iodide.