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julia-pushkina [17]
3 years ago
10

Which of these waves has a disturbance that is both parallel and perpendicular to the wave motion?

Chemistry
2 answers:
Basile [38]3 years ago
7 0
That would be

Answer (B), my friend


A surface wave is a combination of a transverse wave and a longitudinal wave. A transverse wave is a wave in which particles of the medium move up and down perpendicular to the direction of the wave. A longitudinal wave is a wave in which particles of the medium move parallel to the direction of the wave. In a surface wave, particles of the medium move up and down as well as back and forth. This gives them an overall circular motion.
Lorico [155]3 years ago
4 0
The answer would be;

D.) Longitudinal Waves

I Hope This Helps!

Take Care Now, Bye Bye Then.
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A certain amount of NaOH is dissolved in certain kilograms of solvent and molality of the solution is 0.5 m. When the same amoun
mezya [45]

\sf\bold{❍  Given:-}

NaOH is dissolved in certain kilograms of solvent and molality of solution 0.5m.

Again , same among of NaOH is dissolved in 100 grams of solvent than initial , then molality becomes 0.625m.

$\space$

Now lets find the amount of NaOH and the initial mass of solvent.

Let,

  • $\sf\small{Initial\:Mass\:of\:solvent=y}$
  • $\sf\small{Number\:of\:moles\:NaOH\:dissolved=x}$

$\space$

$\sf\bold{ ❍ We\:know,}$

$\sf{Molality(m)=}$ $\sf\dfrac{No.of\:moles\:of\:solute}{No.of\:solvent\:in\:kg}$

$\space$

$\sf\bold{Putting\:the\:formula:-}$

$\space$

$\sf\huge\underline\bold{ ❍Case:1}$

$\space$

$\longmapsto$ $\sf\small{0.5}$ $\sf\dfrac{x}{y}$

$\space$

$\longmapsto$ $\sf{0.5y = x }$

$\space$

$\longmapsto$ $\sf{multiply\:by\:2→ y = 2x}$

$\space$

$\sf\huge\underline\bold{ ❍Case:2}$

$\space$

$\longmapsto$ $\sf\small{0.625}$ $\sf\small\dfrac{x}{y}$ = $\sf\dfrac{x}{y=100g}$

$\space$

$\longmapsto$ $\sf\small{0.625}$ $\sf\dfrac{x}{y-100/1000kg}$ = $\sf\dfrac{x}{y-0.1kg}$

$\space$

$\longmapsto$ $\sf{0.625(y-0.1kg)=x}$

$\space$

$\longmapsto$ $\sf{0.625y-0.0625=x}$

$\space$

$\sf\small\bold{By\:putting\:the\:value\:of \:"x" we\: get:}$

$\space$

$\longmapsto$ $\sf{0.625(2x)-0.0625 = x}$

$\space$

$\longmapsto$ $\sf{1.25x 0.0625 = x}$

$\space$

$\longmapsto$ $\sf{1.25x - x = 0.0625}$

$\space$

$\longmapsto$ $\sf{0.25x = = 0.0625}$

$\space$

$\longmapsto$ $\sf\small{x=}$ $\sf\dfrac{0.0625}{0.25}$= $\sf\bold{x=0.25}$

$\space$

$\sf{So,y=2(x)=2\times0.25=}$ $\sf\bold{y=0.5}$

$\space$

$\sf\small{Initial\:mass\:of\:solvent:0.5kg=500g}$

$\space$

$\sf{Now,}$

<u>A</u><u>m</u><u>o</u><u>u</u><u>n</u><u>t</u><u> </u><u>o</u><u>f</u><u> </u><u>N</u><u>a</u><u>O</u><u>H</u><u>=</u>

$\space$ $\space$ $\space$ $\space$ $\space$ $\sf{=x\times molar\:mass}$

$\space$ $\space$ $\space$ $\space$ $\space$ $\sf{=0.25\times 40=10}$

$\space$

$\sf\underline{\underline{ ⚘ Hence,amount\:of\:NaOH=10kg}}$

_______________________________

8 0
3 years ago
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