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3 years ago

For each chemical equation, which product would be produced?

Chemistry

1 answer:

Eva8 [605]3 years ago

3 0

Answer:

2HBr(g) → H₂ (g) + Br₂ (g)

2Al + Fe₂O₃ → 2Fe + Al₂O₃

2C₄H₆ + 11O₂ → 8CO₂ + 6H₂O

Ag + Pb₃(PO₄)₂ → No reaction

K₂CO₃ + Cal₂ → 2KI + CaCO₃

Explanation:

1st reaction:

2HBr(g) → H₂ (g) + Br₂ (g)

HBr produces hydrogen and bromine gas.

Second reaction:

2Al + Fe₂O₃ → 2Fe + Al₂O₃

Aluminium is more reactive than iron that's why it displace the iron from oxide and form aluminium oxide.

3rd reaction:

2C₄H₆ + 11O₂ → 8CO₂ + 6H₂O

Butyne burn in the presence of oxygen and produces carbondioxide and water.

4th reaction:

Ag + Pb₃(PO₄)₂ → No reaction

Because lead is more more reactive than silver that's why silver can not displace the lead to react with (PO₄)₂ .

5th reaction:

K₂CO₃ + Cal₂ → 2KI + CaCO₃

potassium carbonate react with calcium iodide and produces calcium carbonate and potassium iodide.

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Some car batteries give off a potentially explosive mixture of gases. What kind of change is taking place in the battery?

MrMuchimi

It is chemical change.

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3 years ago

What do many bases have in common?

stepladder [879]

Answer:

All bases conduct electricity as they are good electrolytes. All bases turn red litmus paper into blue at the time of indication. Bases have a bitter taste with a soapy texture

Explanation:

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7 0

3 years ago

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The combustion of ethene in the presence of excess oxygen yields carbon dioxide and water: c2h4 (g) + 3o2 (g) → 2co2 (g) + 2h2o

meriva

Answer:

$\boxed{-267.5}$

Explanation:

You can calculate the entropy change of a reaction by using the standard molar entropies of reactants and products.

The formula is

$\Delta_{r} S^{\circ} = \sum_n {nS_{\text{products}}^{\circ} - \sum_{m} {mS_{\text{reactants}}^{\circ}}}$

The equation for the reaction is

C₂H₄(g) + 3O₂(g) ⟶ 2CO₂(g) + 2H₂O(ℓ)

ΔS°/J·K⁻¹mol⁻¹ 219.5 205.0 213.6 69.9

$\Delta_{r} S^{\circ} = (2\times213.6 + 2\times69.9) - (1\times219.5 + 3\times205.0)\\\\= 567.0 - 834.5 = \boxed{-267.5 \text{ J}\cdot\text{K}^{-1} \text{mol}^{-1}}$

3 0

3 years ago

Complete and balance the molecular equation for the reaction of aqueous sodium sulfate, Na2SO4, and aqueous barium nitrate, Ba(N

Rina8888 [55]

Answer:

1. The balanced molecular equation is given below:

Na2SO4(aq) + Ba(NO3)2(aq) —> BaSO4(s) + 2NaNO3(aq)

2. The net ionic equation is given below:

SO4^2-(aq) + Ba^2+(aq) —> BaSO4(s)

Explanation:

1. The balanced molecular equation

Na2SO4(aq) + Ba(NO3)2(aq) —> BaSO4(s) + NaNO3(aq)

The above equation can be balance as follow:

Na2SO4(aq) + Ba(NO3)2(aq) —> BaSO4(s) + NaNO3(aq)

There are 2 atoms of Na on the left side and 1 atom on the right side. It can be balance by putting 2 in front of NaNO3 as shown below:

Na2SO4(aq) + Ba(NO3)2(aq) —> BaSO4(s) + 2NaNO3(aq)

Now, the equation is balanced.

2. The bal net ionic equation.

This can be obtained as follow:

Na2SO4(aq) + Ba(NO3)2(aq) —>

In solution, Na2SO4 and Ba(NO3)2 will dissociate as follow:

Na2SO4(aq) —> 2Na^+(aq) + SO4^2-(aq)

Ba(NO3)2(aq) —> Ba^2+(aq) + 2NO3^-(aq)

Na2SO4(aq) + Ba(NO3)2(aq) —>

2Na^+(aq) + SO4^2-(aq) + Ba^2+(aq) + 2NO3^-(aq) —> BaSO4(s) + 2Na^+(aq) + 2NO3^-(aq)

Cancel the spectator ions i.e Na^+ and NO3^- to obtain the net ionic equation.

SO4^2-(aq) + Ba^2+(aq) —> BaSO4(s)

7 0

3 years ago

17 points if you say hi to claim points ur gay.

nikitadnepr [17]

Answer:

Explanation:

Boiling point

6 0

3 years ago

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