If you were to graph the sine and cosine functions on the same set of axes, you'd see that they are 90 degrees, or pi/2 radians, out of sync with one another. cos 0 is 1, whereas sin 0 is 0; sin x does not reach the value 1 until your angle reaches 90 degrees, or pi/2 radians.
Please do some experimentation here. You want to express sin (300t) as a cosine, that is, as cos (300t + [some angle]), where [some angle] is called a "phase shift."
Start with the basic y=sin x. Its graph is usually begun at (0,0). Try simplifying and graphing cos (x-pi/2). Does this produce the same y=sin x, with the same graph? Do you remember that
cos (x-pi/2) = cos x cos pi/2 + sin x sin pi/2?
It happens that cos pi/2 = 0 and that sin pi/2 = 1. Thus,
cos (x-pi/2) = sin x (1) = sin x. So, we have succeeded in obtaining sin x from cos (x-pi/2).
Now, what about obtaining sin 300t from the cosine function?
First: recognize that the standard form of the cosine function with a phase shift is y = a cos (bx + c). What is the period?
Answer: The period is always 2pi/b. So, in the case, the period is 2pi/300, or pi/150.
What is the phase shift?
Answer: the period is always -c/b. So, in this case, the period is -c/b, or
-pi/2 over 300. This simplifies to -pi/150.
Try this: Simplify cos (300t -pi/150) If the end result is sin 300t, you'll know you have this right. If the end result is not sin 300t, experiment with that phase shift.
To find the height of the triangle you will use the formula to find the area of the triangle and the information provided about the area and the base length.
A= 1/2 bh
558 = 1/2 x 36 x h
558 = 18 x h
To solve for the height divide both sides by 18.
This leaves you with 31 = h.
So, the height is 31 inches.
If 45 + 47 = t, then t = 45 + 47.....correct
if 45 + 47 < t , then t = 45 + 47....incorrect
45 + 47 < t
92 < t .....this is saying that t is greater then 92
t = 45 + 47
t = 92...this is saying t is equal to 92 (not greater)
D , - if the Fed sells bonds, it decreases the money supply by removing cash from the economy in exchange for bonds.
<span>
</span>
Idk if this helped you but , symmetric forms a mirror image of itself when reflected in its vertical line ( u shape ) and symmetric bell shaped is when you draw the vertical line at the center
