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4 years ago

Need help with this pls (Show work pls!!)

Mathematics

1 answer:

Aleksandr-060686 [28]4 years ago

7 0

This is my first time on this app but this question doesn’t look to hard i’m ok at math but not that good at showing my work

Isosceles triangles have to equal sides

and each side is 5 cm greater than the base

you know the perimeter is 46

i would use basic algebra

x = base

46 = 2(x +5) + x

the 2(x +5) is the equal sides

46 = 2(x+5) + x

using distributive property

46 = 2x + 10 + x

add the common variable

46 = 3x + 10

now it’s easy

3x = 46 - 10

3x = 36

x = 36 / 3

x = 12

now that we got x (base)

we know that the equal sides are 5 cm longer than the base

12 + 5 = 17

since there are 2 sides and they are equal they are both 17

so each side of the triangle would be
1. 17 cm
2. 17 cm
3. 12 cm

to check you should be able to add them all together and get 46

17 + 17 + 12 = 46

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Find the zeros of f(x)=-x^2+6x+27

lara31 [8.8K]

Answer:

Zeroes of this function are -3 and 9.

Step-by-step explanation:

Using quadratic formula we have:

(-6 +- $\sqrt{6^{2}-4(-1)(27) }$ ) / 2(-1)

= -3, 9

4 0

3 years ago

Use properties to rewrite the given equation. Which equations have the same solution as 3/5x +2/3 + x = 1/2– 1/5x? Check all tha

vodomira [7]

we have

$\frac{3}{5}x+ \frac{2}{3}+x=\frac{1}{2}-\frac{1}{5}x$

Combine like terms in both sides

$(\frac{3}{5}x+ x)+\frac{2}{3}=\frac{1}{2}-\frac{1}{5}x$

we know that

$(\frac{3}{5}x+ x)=(\frac{3}{5}x+ \frac{5}{5}x)=\frac{8}{5}x$

substitute in the expression above

$\frac{8}{5}x+\frac{2}{3}=\frac{1}{2}-\frac{1}{5}x$ -----> equation A

Multiply equation A by $5*3*2=30$ both sides

$30*(\frac{8}{5}x+\frac{2}{3})=30*(\frac{1}{2}-\frac{1}{5}x)$

$48x+20=15-6x$ ---------> equation B

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$48x+6x=15-20$

$54x=-5$ ---------> equation C

Solve for x

$x=-\frac{5}{54} =-0.09$

We are going to proceed to verify each case to determine the solution.

Case a) $\frac{8}{5}x+\frac{2}{3}=\frac{1}{2}-\frac{1}{5}x$

the case a) is equal to the equation A

the case a) have the same solution that the given equation

Case b) $18x+20+30x=15-6x$

Combine like terms in left side

$(18x+30x)+20=15-6x$

$(48x)+20=15-6x$

the case b) is equal to the equation B

the case b) have the same solution that the given equation

Case c) $18x+20+x=15-6x$

Combine like terms in left side

$(18x+x)+20=15-6x$

$(19x)+20=15-6x$

$19x+6x=15-20\\25x=-5\\x=-0.20$

$-0.20\neq -0.09$

therefore

the case c) not have the same solution that the given equation

Case d) $24x+30x=-5$

Combine like terms in left side

$54x=-5$

the case d) is equal to the equation C

the case d) have the same solution that the given equation

Case e) $12x+30x=-5$

Combine like terms in left side

$42x=-5$

$x=-5/42=-0.12$

$-0.12\neq -0.09$

therefore

the case e) not have the same solution that the given equation

therefore

the answer is

case a) $\frac{8}{5}x+\frac{2}{3}=\frac{1}{2}-\frac{1}{5}x$

case b) $18x+20+30x=15-6x$

case d) $24x+30x=-5$

7 0

4 years ago

Read 2 more answers

??????need help plz

Yuki888 [10]

Answer:

36%

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Suppose a teacher finds that the

horsena [70]

Answer:

Scores = 8

Step-by-step explanation:

To solve variation problems, you make mild assumptions and analogies

Let's score be represented with S

Let's Absences be represented with A.

Therefore

S varies inversely as A

S ~ 1/A

S = K/A

The K represents a contant notation so that we can easily figure the variation problem.

When Absences were 2

Scores were 12

S = K/A

12 = K / 2

Cross Multiply.

K = 24.

It means that, S = 24 / A.

For a student with 3 absences, the score would be:

S = 24 / A

S = 24 / 3

S = 8

Math is fun!

5 0

4 years ago

Find the missing side length

sasho [114]

Answer:

Missing side length = 54

Step-by-step explanation:

If both the triangles given in the picture are similar their corresponding sides will be proportional.

By applying this rule in the given similar triangles,

$\frac{35}{30}=\frac{49}{42}=\frac{63}{6x-6}$

$\frac{7}{6}=\frac{7}{6}= \frac{63}{6x-6}$

$\frac{7}{6}= \frac{63}{6x-6}$

$\frac{1}{6}= \frac{9}{6x-6}$

$\frac{1}{6}= \frac{9}{6(x-1)}$

$1=\frac{9}{x-1}$

$x-1=9$

$x=10$

Therefore, missing side length = $6x-6$

= $6(x-1)$

= $6(10-1)$

= $6\times 9$

= $54$

4 0

3 years ago