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3 years ago

Television sizes are labeled by the measure of the diagonal

Mathematics

1 answer:

Fittoniya [83]3 years ago

8 0

Answer:

C. 55 inches

Step-by-step explanation:

a^2 = b^2 + c^2

a^2 = 47.5^2 + 27^2

a^2 = 2985.25

a = 54.637 = 55 inches

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What is the least common denominator (LCD)

Romashka [77]

The least common denominator is 15. The equivalent fractions would be 10/15 and 12/15.

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3 years ago

Mr. Anderson wrote (7x9) 103 on the board. What is the value of that expression

RUDIKE [14]

Answer:

6,489

Step-by-step explanation:

first you would multiply 7 and 9, which would be 63

7 x 9 = 63

then you would multiply 63 by 103 since they are being multiplied

63 x 103 = 6,489

8 0

3 years ago

if the probability of picking a green marble from a bag of green and red marbles is 0.3. if i choose a marble 100 times and repl

vfiekz [6]

Answer:

30 marbles would be green

Step-by-step explanation:

green chance is 0.3

red chance 0.7

.3 times 100

30 green marbles is what you would expect

7 0

3 years ago

How to put 17/4 into a mixed number

KiRa [710]

Divide the top by bottom. So 17 divided by 4. Which would be around 4.25

4 0

3 years ago

Read 2 more answers

Consider the following hypothesis test:

Gnom [1K]

Answer:

a. z=3.09. Yes, it can be concluded that the population mean is greater than 50.

b. z=1.24. No, it can not be concluded that the population mean is greater than 50.

c. z=2.22. Yes, it can be concluded that the population mean is greater than 50.

Step-by-step explanation:

We have a hypothesis test for the mean, with the hypothesis:

$H_0: \mu\leq50\\\\H_a:\mu> 50$

The sample size is n=55 and the population standard deviation is 6.

The significance level is 0.05.

We can calculate the standard error as:

$\sigma_M=\dfrac{\sigma}{\sqrt{n}}=\dfrac{6}{\sqrt{55}}=0.809$

For a significance level of 0.05, the critical value for z is zc=1.644. If the test statistic is bigger than 1.644, the null hypothesis is rejected.

a. If the sample mean is M=52.5, the test statistic is:

$z=\dfrac{M-\mu}{\sigma_M}=\dfrac{52.5-50}{0.809}=\dfrac{2.5}{0.809}=3.09$

The null hypothesis is rejected, as z>zc and falls in the rejection region.

b. If the sample mean is M=51, the test statistic is:

$z=\dfrac{M-\mu}{\sigma_M}=\dfrac{51-50}{0.809}=\dfrac{1}{0.809}=1.24$

The null hypothesis failed to be rejected, as z<zc and falls in the acceptance region.

c. If the sample mean is M=51.8, the test statistic is:

$z=\dfrac{M-\mu}{\sigma_M}=\dfrac{51.8-50}{0.809}=\dfrac{1.8}{0.809}=2.22$

The null hypothesis is rejected, as z>zc and falls in the rejection region.

8 0

4 years ago