Question

Based on the dartboard shown below, what is the probability of a random throw hitting a section that is yellow or 1?

Answer 1

Since the events are mutually exclusive (you can't hit a yellow section and 1 section at the same time), we can add the probabilities of both A (hitting a yellow section) and B (hitting a section with a 1).

$P(A) = \frac{2}{8}$
$P(B) = \frac{4}{8}$

Thus, the probability of hitting a yellow section or a section with a 1 is $\frac{2}{8} + \frac{4}{8} = \boxed{\frac{6}{8}}$.